Answer:
y = 2x + 3
Step-by-step explanation:
In the slope-intercept form of the equation of a line,
y = mx + b,
m = slope, and b = y-intercept.
Let's look at Adriana's equation and understand the parts:
y = 2x + 4
y = mx + b
m = slope = 2; b = y-intercept = 4
Now let's look at the description of Henry's equation.
He has the same slope as Adriana, so for Henry, m = 2 also.
His y-intercept is 1 less than Adriana's, so it is 1 less than 4. Henry's y-intercept is 3.
Now that we know that for Henry, m = 2, and b = 3, we can write his equation.
y = mx + b
y = 2x + 3
Answer: y = 2x + 3
Answer:
B
Step-by-step explanation:
because the angles 1 and 7 are alternate and equal , we can conclude that p and q are parralel
11 school days are left.
In the attached picture of a calendar, I marked the days the person has left. There are 11.
Answer:
Find the complete table in attached file.
Step-by-step explanation:
Find the Incomplete table in attached file
Given:
A car travels 55 miles per hour for 2 hours.
So the speed of the car 55 miles per hour is constant for 2 hours.
Using speed formula.
![Speed=\frac{distance}{time}](https://tex.z-dn.net/?f=Speed%3D%5Cfrac%7Bdistance%7D%7Btime%7D)
Second row.
From the second row of the table
and speed is constant
, so we need to find only distance.
![Speed=\frac{distance}{time}](https://tex.z-dn.net/?f=Speed%3D%5Cfrac%7Bdistance%7D%7Btime%7D)
![55=\frac{distance}{0.5}](https://tex.z-dn.net/?f=55%3D%5Cfrac%7Bdistance%7D%7B0.5%7D)
![distance = 55\times 0.5](https://tex.z-dn.net/?f=distance%20%3D%2055%5Ctimes%200.5)
![distance = 27.5\ mi](https://tex.z-dn.net/?f=distance%20%3D%2027.5%5C%20mi)
Third row.
From the third row of the table
and speed is constant
, so we need to find only distance.
![Speed=\frac{distance}{time}](https://tex.z-dn.net/?f=Speed%3D%5Cfrac%7Bdistance%7D%7Btime%7D)
![55=\frac{distance}{1.5}](https://tex.z-dn.net/?f=55%3D%5Cfrac%7Bdistance%7D%7B1.5%7D)
![distance = 55\times 1.5](https://tex.z-dn.net/?f=distance%20%3D%2055%5Ctimes%201.5)
![distance = 82.5\ mi](https://tex.z-dn.net/?f=distance%20%3D%2082.5%5C%20mi)
Fourth row.
From the fourth row of the table
and speed is constant
, so we need to find time.
![Speed=\frac{distance}{time}](https://tex.z-dn.net/?f=Speed%3D%5Cfrac%7Bdistance%7D%7Btime%7D)
![time=\frac{distance}{speed}](https://tex.z-dn.net/?f=time%3D%5Cfrac%7Bdistance%7D%7Bspeed%7D)
![time=\frac{110}{55}](https://tex.z-dn.net/?f=time%3D%5Cfrac%7B110%7D%7B55%7D)
![time = 2\ sec](https://tex.z-dn.net/?f=time%20%3D%202%5C%20sec)
Therefore we complete the table from the above calculation.