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kramer
3 years ago
5

What is the solution to the system of equations below?

Mathematics
2 answers:
Kipish [7]3 years ago
7 0

Answer:

(18,0)

Step-by-step explanation:

Karolina [17]3 years ago
3 0

Answer:

The solution is the point (18,0)

Step-by-step explanation:

we have

y=-\frac{1}{3}x+6 -----> equation A

y=\frac{1}{3}x-6 -----> equation B

Solve the system by substitution

substitute equation B in equation A

\frac{1}{3}x-6=-\frac{1}{3}x+6

solve for x

Adds (1/3)x both sides

\frac{1}{3}x-6+\frac{1}{3}x=6

\frac{2}{3}x-6=6

Adds 6 both sides

\frac{2}{3}x=6+6

\frac{2}{3}x=12

x=12(3)/2\\x=18

<em>Find the value of y</em>

substitute the value of x in equation A or equation B

y=-\frac{1}{3}(18)+6=0

therefore

The solution is the point (18,0)

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5 0
3 years ago
I'm answering any 5th grade and below questions​
Anestetic [448]

Answer:

In at least one hundred words, describe how what Markandaya reveals about Kenny helps to shape his character, and which themes in Nectar in a Sieve are developed with this information.

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3 0
3 years ago
Find how many six-digit numbers can be formed from the digits 2, 3, 4, 5, 6 and 7 (with repetitions), if:
Goshia [24]

Answer:

case 1 = 2592

case 2 =  729

case 1 + case 2 =  2916

(this is not a direct adition, because case 1 and case 2 have some shared elements)

Step-by-step explanation:

Case 1)

6 digits numbers that can be divided by 25.

For the first four positions, we can use any of the 6 given numbers.

For the last two positions, we have that the only numbers that can be divided by 25 are numbers that end in 25, 50, 75 or 100.

The only two that we can create with the numbers given are 25 and 75.

So for the fifth position we have 2 options, 2 or 7,

and for the last position we have only one option, 5.

Then the total number of combinations is:

C = 6*6*6*6*2*1 = 2592

case 2)

The even numbers are 2,4 and 6

the odd numbers are 3, 5 and 7.

For the even positions we can only use odd numbers, we have 3 even positions and 3 odd numbers, so the combinations are:

3*3*3

For the odd positions we can only use even numbers, we have 3 even numbers, so the number of combinations is:

3*3*3

we can put those two togheter and get that the total number of combinations is:

C = 3*3*3*3*3*3 = 3^6 = 729

If we want to calculate the combinations togheter, we need to discard the cases where we use 2 in the fourth position and 5 in the sixt position (because those numbers are already counted in case 1) so we have 2 numbers for the fifth position and 2 numbers for the sixt position

Then the number of combinations is

C = 3*3*3*3*2*2 = 324

Case 1 + case 2 = 324 + 2592 = 2916

4 0
3 years ago
If f(x) = 4x-9, evaluate f(3) <br>I need HELP ASAP!!!!!!!!!!!​
seropon [69]

Answer:

substitute 3 as in x:

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Hope this helped - have a nice day & be safe

8 0
3 years ago
Item 8
ludmilkaskok [199]
So, I didn't quite understand your question clearly, but I'll try my best to answer it.

So, the first question is quite simple: Did the runner have a % decrease in his time or an increase.
Well, 7:45 is minor than 5:51. So, his time decreased.

2nd question:
The percent of change. Well, first things first 7:45 has 2 different units, wich are minutes and seconds, I suppose. Same goes for 5:51.
So let's put everything in seconds. multiply both the 7 and 5 for 60(for every minute has 60 seconds.)

That means:
7*60= 420+45 = 465.
5*60=300+51=351.

Now, let's do the math itself:
465 -> 100%
351 -> x%
 Is equal to about  75,5%
How much did it decrease then?
(75,5-100)%= 24,5%, approximately

8 0
3 years ago
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