All categories

2 years ago

Select the correct answer.

Mathematics

1 answer:

miv72 [106K]2 years ago

4 0

The 24 walls must paint by each volunteer if the work is divided evenly and the club has 36 volunteers.

<h3>What is a fraction?</h3>

Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

We have:

As part of a community-service project, a local club has decided to paint 864 walls across town. The club has 36 volunteers.

Total number of volunteers = 36

Number of walls = 864

The number of walls each volunteer paint can be expressed as a fraction:

= 864/36

= 24

Thus, the 24 walls must paint by each volunteer if the work is divided evenly and the club has 36 volunteers.

Learn more about the fraction here:

brainly.com/question/1301963

#SPJ1

Read more about transformation at:

brainly.com/question/4289712

8 0

3 years ago

Radius of a sphere that has a surface area 12.56in2 use 3.14

enot [183]

$\bf \textit{surface area of a sphere}\\\\
A=4\pi r^2\qquad 
\begin{cases}
r=radius\\
-----\\
A=12.56
\end{cases}\implies 12.56=4\pi r^2
\\\\\\
\cfrac{12.56}{4\pi }=r^2\implies \sqrt{\cfrac{12.56}{4\pi }}=r$

8 0

3 years ago

Can someone help me answer this

VikaD [51]

C

Your welcome lolololololol

8 0

3 years ago

Read 2 more answers

Show how to use substitution or elimination to solve the following system of equations. Write the solution as an ordered pair.

max2010maxim [7]

Answer:

(4, 6)

Step-by-step explanation:

<u>Substitution</u>

Using the second equation, we can substitute for y in the first equation.

4x -(2x-2) = 10

2x +2 = 10 . . . . simplify

x +1 = 5 . . . . . . .divide by 2

x = 4 . . . . . . . . . subtract 1

y = 2(4) -2) = 6 . . . . substitute for x in the equation for y

The solution is (x, y) = (4, 6).

<u>Elimination</u>

Often, we like to start with both equations in standard form when we solve by elimination. That is nice, but not completely necessary.

We can eliminate the y-variable by simply adding the two given equations.

(4x -y) +(y) = (10) +(2x -2)

4x = 8 + 2x . . . . . collect terms. The y-variable has been eliminated.

2x = 8 . . . . . . . . . subtract 2x

x = 4 . . . . . . . . . . divide by 2

Y can be found using the second equation.

(x, y) = (4, 6)

We could have eliminated the x-variable by multiplying the second equation by 2, then adding the two equations.

(4x -y) +2(y) = (10) +2(2x -2)

y = 6 . . . . . . . . . subtract 4x from both sides. The x-variable has been eliminated.

Now, x can be found using either equation.

6 = 2x -2 . . . substitute for y in the second equation

3 = x - 1 . . . divide by 2

x = 4 . . . . . add 1

(x, y) = (4, 6)

3 0

3 years ago

Initially, there are 40 grams of A and 50 grams of B, and for each gram of B, 2 grams of A is used. It is observed that 15 grams

hram777 [196]

Answer:

$X(16)=25.71grams$

Step-by-step explanation:

let $X(t)$ denote grams of $C$ formed in $t$ mins.

For $X grams$ of $C$ we have:

$\frac{2}{3}Xg$ of A and $\frac{1}{3}Xg$ of B

Amounts of A,B remaining at any given time is expressed as:

$40-\frac{2}{3}Xg$ of A and $50-\frac{1}{3}Xg$ of B

Rate at which C is formed satisfies:

$\frac{dX}{dt} \infty(40-\frac{2}{3}X)(50-\frac{1}{3}X)->\frac{dX}{dt}=k(90-X)\\\therefore \frac{dX}{(90-X)^2}=kdt->\int{\frac{dX}{(90-X)^2}} \, =\int {k} \, dt \\\therefore \frac{1}{90-X}=kt+c->90-X=\frac{1}{kt+c}\\\\X(t)=90-\frac{1}{kt+c}$

Apply the initial condition, $X(0)=0$ ,to the expression above

$0=90-\frac{1}{c} \ \ ->c=\frac{1}{90}\\\therefore\\X(t)=90-\frac{1}{kt+\frac{1}{90}} \ \ ->X(t)=90-\frac{90}{90kt+c}$

Now at $X(8)=15$ :

$15=90-\frac{90}{90\times 8k+1} \ ->75=\frac{90}{720k+1}\\k=0.0002778$

Substitute in X(t) to get

$X(t)=90-\frac{90}{0.0002778t\times 90+1}\\X(t)=90-\frac{90}{0.25t+1}\\But \ t=16\\\therefore X(t)=90-\frac{90}{0.025\times16+1}\\X(t)=25.71$

5 0

3 years ago