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3 years ago

Please help! (image is for question 3)

Mathematics

2 answers:

nika2105 [10]3 years ago

6 0

The formula for the total sum of the inner angles of the polygon is

Sn= (n-2) 180°

1) S6= (6-2) 180 = 4*180 = 720° In the hexagon all angles are equal

α= S6/6= 720/6= 120°

2) In each polygon the sum of the external angles is 360°

3) S5= (5-2) 180 = 540° than we can add up all angles

x+131+108+107+110=540 => x= 540-456= 84°

4) α = 360/5=72°

Good luck!!!

Nata [24]3 years ago

3 0

Answer:

i got a 40%on the test.. what did you get?

Step-by-step explanation:

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The mean cost of a five pound bag of shrimp is 46 dollars with a variance of 64. If a sample of 53 bags of shrimp is randomly se

sertanlavr [38]

Answer:

The probability that sample mean differ the true greater than 2.1 will be 2.8070 %

Step-by-step explanation:

Given:

Sample mean =46 dollars

standard deviation=8

n=53

To Find :

Probability that sample mean would differ from true mean by greater than 2.1

Solution;

<em>This sample distribution mean problem,</em>

so for that

calculate Z- value

Z=(sample mean - true mean)/(standard deviation/Sqrt(n))

Z=-2.1/(8/Sqrt(53))

Z=-2.1*Sqrt(53)/8

Z=-1.91102

Now for P(X≥2.1)=P(Z≥-1.91102)

Using Z-table,

For Z=-1.91

P(X>2.1)=0.02807

6 0

3 years ago

A factory received a shipment of 11 hammers, and the vendor who sold the items knows there are 2 hammers in the shipment that ar

zhenek [66]

Question:

If a sample of 2 hammer is selected

(a) find the probability that all in the sample are defective.

(b) find the probability that none in the sample are defective.

Answer:

a $Pr = \frac{2}{110}$

b $Pr = \frac{72}{110}$

Step-by-step explanation:

Given

$n = 11$ --- hammers

$r = 2$ --- selection

This will be treated as selection without replacement. So, 1 will be subtracted from subsequent probabilities

Solving (a): Probability that both selection are defective.

For two selections, the probability that all are defective is:

$Pr = P(D) * P(D)$

$Pr = \frac{2}{11} * \frac{2-1}{11-1}$

$Pr = \frac{2}{11} * \frac{1}{10}$

$Pr = \frac{2}{110}$

Solving (b): Probability that none are defective.

The probability that a selection is not defective is:

$P(D') = \frac{9}{11}$

For two selections, the probability that all are not defective is:

$Pr = P(D') * P(D')$

$Pr = \frac{9}{11} * \frac{9-1}{11-1}$

$Pr = \frac{9}{11} * \frac{8}{10}$

$Pr = \frac{72}{110}$

8 0

2 years ago

A man sells a sofa for rs 3210 making a profit of 7% what would have been his profit percent if he had sold it for rs 3360?

Digiron [165]

Let x be the original cost for the sofa.
X x (1 + 0.07) =3210
X = 3000
Now we know the cost for the sofa.
Let p be the profit percent.
3000 x (1 + p) = 3360
P = 0.12
So the percentage profit is 12%

7 0

3 years ago

2(x-3)=1/2(4x-12)<br>please help MEH!!!!!....

Zinaida [17]

Answer:

infinitely many solutions

Step-by-step explanation:

2(x-3)=1/2(4x-12)

2x-6=2x-6

both sides are the same so its infinitely many solutions

8 0

3 years ago

If charged per cut, how much will it cost

melisa1 [442]

Answer:

24 because if your cutting 8 pieces and 4 pieces is 12 then all you have to do is multiply 12 x 2 which equals 24!

Step-by-step explanation:

7 0

2 years ago