2 years ago

Can someone explain

Mathematics

1 answer:

anzhelika [568]2 years ago

5 0

It's d ok
$- 900$

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JKLM is a rhombus. KM is 20 and JL is 48. Find the perimeter of the<br><br> rhombus.

anygoal [31]

Answer:

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Step-by-step explanation:

Given

Shape: Rhombus

$JL = 48$

$KM = 20$

Required

Determine the perimeter

The given parameter are the diagonals of the rhombus.

The perimeter (from diagonals) is calculated as thus:

$P = 2\sqrt{(JL)^2 + (KM)^2}$

Substitute values for JL and KM

$P = 2\sqrt{48^2 + 20^2}$

$P = 2\sqrt{2304 +400}$

$P = 2\sqrt{2704}$

$P = 2 * 52$

$P = 104$

<em>Hence, the perimeter is 104 units</em>

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