Can someone explain
1 answer:
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Answer:
sin-¹(10/11)
Step-by-step explanation:
The height of the building is 100 ft and the ladder is 110ft long .We can imagine this situation as a right angled ∆. For figure refer to the attachment .
- We can use ratio sine here. Let the angle of elevation be theta.
<u>In </u><u>∆</u><u> </u><u>ABC </u><u>:</u><u>-</u><u> </u>
=> sinθ = p/h
=> sinθ = 100ft / 110 ft
=> sinθ = 10/11
=> θ = sin -¹ ( 10/11) .
<h3><u>Hence </u><u>the</u><u> </u><u>angle</u><u> of</u><u> elevation</u><u> </u><u>is </u><u>sin </u><u>-</u><u>¹</u><u> </u><u>(</u><u> </u><u>1</u><u>0</u><u>/</u><u>1</u><u>1</u><u>)</u><u>. </u><u> </u></h3>
Answer:
<h2>i) 3</h2><h2>ii) 5</h2>Step-by-step explanation:
Let H be the set of students who play Hokey
V be the set of students who play Volleyball
S be the set of students who play Soccer
======================================
card(volleyball only) = card(V) - [card(V∩H∩S) + card(V∩H only) + card(V∩S only)]
= 73 - [50 + (58-50) + (62-50)]
= 73 - [50 + 8 + 12]
= 73 - 70
= 3
………………………………………………
Card(Hokey only) = 100 - [3 + 8 + 50 + 10 + 12 + 12]
= 100 - 95
= 5
…………………
<u><em>Note</em></u> :
A Venn diagram might be helpful in such case.
