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crimeas [40]
3 years ago
5

Vanessa draws one side of equilateral AABC on the coordinate plane at points A(-2, 1) and B(4,1). What are the possible coordina

tes of vertex C? Select all that apply.​

Mathematics
2 answers:
77julia77 [94]3 years ago
8 0
I agree with the other commenter E is the closet thing
natulia [17]3 years ago
7 0

Answer:

Step-by-step explanation:

Answer E is the only one that is close

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A city lot is 20 4/5 meters wide. It is 2 1/2 times as long as it is wide. How long is the city lot? Express your answer in simp
blsea [12.9K]

Answer:

41 6/10 or 41 3/5

both answered are the same, just simplified it

Step-by-step explanation:

20 4/5 x 2= 41 6/10 or 41 3/5

3 0
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Which of the following statements is true?
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19x^3 + (14x + 4x^3) =
Brrunno [24]
19x³ + (14x + 4x³)=
You can assume that there is a 1 in front of the parentheses, so you can distribute the one to each term in the parentheses.
19x³ + 1(14x+4x³)=
19x³ + 14x + 4x³=
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sergiy2304 [10]

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Step-by-step explanation:

8 0
3 years ago
The Edward James Toy Company uses a Kanban system to make plastic wheels that are a component of several toys. The waiting time
pickupchik [31]

Answer:

N_c \approx 5.0

Step-by-step explanation:

From the question we are told that:

Waiting time for a container of the wheels during production T_w=0.25day

Average processing time is T_a=0.15 day per container

Wheel per container N_w=200

Total wheel per day D=2000

Policy variable of X=5%  

Generally the equation for Total number of container N_c is mathematically given by

N_c=DT(\frac{1+X}{N_w} )

Where

Total time T=T_w+T_a

T=0.15+0.25

Therefore

N_c=DT(\frac{1+X}{N_w} )

N_c=2000*0.40(\frac{1+0.5}{200} )

N_c=(\frac{840}{200} )

N_c=4.2

N_c \approx 5.0

Therefore the number of Kanban containers needed for the wheels is

N_c \approx 5.0

3 0
3 years ago
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