Ask question

Ask question

All categories

2 years ago

5

Vanessa draws one side of equilateral AABC on the coordinate plane at points A(-2, 1) and B(4,1). What are the possible coordina

tes of vertex C? Select all that apply.

2 answers:

77julia77 [94]2 years ago

8 0

I agree with the other commenter E is the closet thing

natulia [17]2 years ago

7 0

Answer:

Step-by-step explanation:

Answer E is the only one that is close

You might be interested in

Pls help. need explanation too pls

FrozenT [24]

Answer:

-3 ≤ x ≤ 13

Step-by-step explanation:

<u>Values on x- axis between -3 and 13 both numbers included:</u>

x = [-3, 13]
-3 ≤ x ≤ 13

5 0

2 years ago

What is the value of 8x135

umka21 [38]

It would be 1080

Just use a calculator

6 0

3 years ago

Read 2 more answers

Evaluate<br> —2y – 3x for x = 1 and y= -2.<br><br> The value of the expression is

bulgar [2K]

Answer:

1

Step-by-step explanation:

Given

- 2y - 3x ← substitute x = 1 and y = - 2 into the expression

= - 2(- 2) - 3(1)

= 4 - 3

= 1

7 0

2 years ago

Is 5/6 closest to 0,1/2, and 1

Ne4ueva [31]

I think the answer is 1.First, find the least common denominator, which is 6. Then, multiply the numerator and denominator by the same number to get 6 as the denominator. $\frac{0}{1}$ is multiplied by 6 to get $\frac{0}{6}$ . $\frac{1}{2}$ is multiplied by 3 to get $\frac{3}{6}$ . $\frac{1}{1}$ is multiplied by 6 to get $\frac{6}{6}$ . Since $\frac{5}{6}$ is closest to $\frac{6}{6}$ , 1 is the answer. Hope this helps!

5 0

2 years ago

The population of algae in an experiment has been increasing by 5% each day. If there were 5p algae at the beginning of the expe

Ostrovityanka [42]

Answer:

Number of algae in 7 days = 70.355

Step-by-step explanation:

Given:

Algae in beginning = 50

Rate of increasing = 5% per day = 0.05

Number of days = 7 days

Find:

Number of algae in 7 days.

Computation:

$Number\ of\ algae\ in\ 7\ days = Algae\ in\ beginning(1+Rate\ of\ increasing)^{Number\ of\ days}\\\\Number\ of\ algae\ in\ 7\ days = 50(1+0.05)^7\\\\Number\ of\ algae\ in\ 7\ days = 70.355$

Number of algae in 7 days = 70.355

4 0

2 years ago