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3 years ago

Help 19 x 22 using algorithm!?

Mathematics

2 answers:

Aliun [14]3 years ago

4 0

Answer:

418 because just multiply it

ikadub [295]3 years ago

3 0

Answer:

418

Step-by-step explanation:

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One survey showed that among 785 randomly selected subjects who completed four years of college, 18.3% smoke and a 98% confidenc

Valentin [98]

Answer

a. True

Step-by-step explanation:

Based on this survey we estimate that about $18.3\%$ of the college students smokes. And a $98\%$ confidence interval is $[15.1\% ; 21.6\%]$ . So we know that our estimative for the smoking rate is in the confidence interval with $98\%$ certainty. We also know the estimative for the smoking rate in the general population is $27\%$ . So we can write the two possible hypothesis:

$H_0 =$ Smoking rate is equal to $27\%$ .

$H_1 =$ Smoking rate is not equal to $27\%$ .

We will reject the null hypothesis $(H_0)$ if the estimate doesn't fall into the confidence interval for the college students smoking rate.

Since this condition holds we reject the null hypothesis. So with $98\%$ certainty we say that the smoking rate for the general population is different than the smoking rate for the college students.

6 0

3 years ago

Find the greatest common factor 7x^3a+7x^2a^2

muminat

Answer:

7x^2a

Step-by-step explanation:

7x^3a+7x^2a^2

7x^3a = 7 xxxa

7x^2a^2= 7 xxaa

The common terms are 7xxa

7x^2a

This is the greatest common factor

6 0

3 years ago

What is the final cost of the less expensive option?

Debora [2.8K]

The answer is d I think but idk

7 0

3 years ago

The variables x and y vary inversely If x=5 when y=12, then find the value of x when y=32

Vilka [71]

Answer:

x=15/8

Step-by-step explanation:

Inverse variation is given by

xy = k

Substituting x=5 and y=12

5*12 = k

60 =k

Our original equation is xy = 60

Now let y=32

x*32 = 60

Divide each side by 32

32x/32 = 60/32

Divide top and bottom by 4

x = 15/8

4 0

4 years ago

businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message

KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let X = number of text messages receive or send in an hour.

The random variable X follows a Poisson distribution with parameter λ.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: $\lambda=\frac{62.7}{24}= 2.6125$ .

The probability of a random variable can be computed using the formula:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...$

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

$P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180$

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

= 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

$=1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667$

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0

3 years ago