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jasenka [17]
3 years ago
7

Domain: {4, 0} range: (-2, 0, 2}

Mathematics
2 answers:
uysha [10]3 years ago
7 0
I believe the answer is C
Dmitry_Shevchenko [17]3 years ago
4 0

Answer:

C

Step-by-step explanation:

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It is asking what is the relationship between segment pq and p”q’
nadezda [96]

angles it sounds like but ik the struggle

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4 years ago
In problems 1-3, a and b are legs and c is the hypotenuse. Find the missing side length of the
Readme [11.4K]

Answer:

1. b=39.497

2. c=3.606

3. a=18.974

Step-by-step explanation:

1.

41^2-11^2=b^2

1681-121=b^2

b^=1560

b=39.497

2.

2^2+3^2=c^2

4+9=c^2

c^2=13

c=3.606

3.

21^2-9^9=a^2

441-81=a^2

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4 0
3 years ago
This rectangle represents the base of a rectangular prism. The height of the rectangular prism is 56 m.
elena-14-01-66 [18.8K]

Answer:

1,960

Step-by-step explanation:

35 times 56 = 1,960

35 is the base, to get the base you do length times width.

the height is 56. To get the volume do base (or length times width) times hight.

Hope that helps!

5 0
3 years ago
Read 2 more answers
Which expressions are equivalent to 5+ (-3)(6x – 5)?
Viefleur [7K]

Hello

5 + ( -3) ( 6x - 5 )

= 5 - 3*6x + 5*3

= -18x + 20

Good day. ;)

4 0
3 years ago
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The answer to these please!
igomit [66]
\sqrt[4]{(4a^{2})^{6}} = \sqrt[4]{4096a^{12}} = 8a^{3}

\sqrt[7]{(b^{\frac{5}{3}})^{8}} = \sqrt[7]{b^\frac{40}{3}} = b^{\frac{40}{21}} = \sqrt[21]{b^{40}} = \sqrt[21]{b^{21} * b^{19}} = \sqrt[21]{b^{21}} \sqrt[21]{b^{19}} = b\sqrt[21]{b^{19}}

\sqrt[3]{\frac{c^{9}}{c^{3}}} = \sqrt[3]{c^{6}} = c^{2}

\sqrt[3]{27d^{6} * 8d^{-4}} = \sqrt[3]{27d^{6} * \frac{8}{d^{4}}} = \sqrt[3]{216d^{2}} = 6\sqrt[3]{d^{2}} = 6d^{\frac{2}{3}}
4 0
3 years ago
Read 2 more answers
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