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erastovalidia [21]
3 years ago
11

the basketball court in the park is rectangle two of the sides are 84 feet long and the other two sides are 50 ft long what is t

he perimeter of the basketball court
Mathematics
1 answer:
butalik [34]3 years ago
6 0
Hello!

So, we know that the length of the rectangular basketball court is 84 ft, and the width is 50 ft.

The formula for perimeter of a rectangle is:

P = 2l + 2w

This means that we need to multiply the length by two and the width by two as well.

Substitute:

P = 2(84) + 2(50)

P = 168 + 100

P = 268 ft

ANSWER:

The perimeter of the basketball court is 268 feet long.
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loris [4]

Answer:

<em>The coordinates of the vertex are (-1,-4).</em>

Step-by-step explanation:

<u>Equation of the Quadratic Function </u>

The vertex form of the quadratic function has the following equation:

y-k=a(x-h)^2

Where (h, k) is the vertex of the parabola that results when plotting the function, and a is a coefficient different from zero.

We are given the function:

y=x^2+2x-3

We must transform the equation above by completing squares:

The first two terms can be completed to be the square of a binomial. Recall the identity:

x^2+2xy+y^2=(x+y)^2

Thus if we add and subtract 1:

y=(x^2+2x+1)-3-1

Operating:

y=(x^2+2x+1)-4

The trinomial in parentheses is a perfect square:

y=(x+1)^2-4

Adding 4:

y+4=(x+1)^2

Comparing with the vertex form of the quadratic function, we have the vertex (-1,-4).

The coordinates of the vertex are (-1,-4).

4 0
2 years ago
A leak in a pool causes the height of the water to decrease by 0.25 foot over 2 hours. After the leak is fixed, the height of th
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  5 feet

Step-by-step explanation:

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The original height of the water in the pool was 5.00 feet.

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Find the constant $a$ such that\[(x^2 - 3x + 4)(2x^2 +ax + 7) = 2x^4 -11x^3 +30x^2 -41x +28.\]
Colt1911 [192]

The value of constant a is -5

Further explanation:

We will use the comparison of co-efficient method for finding the value of a

So,

Given

(x^2 - 3x + 4)(2x^2 +ax + 7)\\= x^2((2x^2 +ax + 7)-3x((2x^2 +ax + 7)+4(2x^2 +ax + 7)\\= 2x^4+ax^3+7x^2-6x^3-3ax^2-21x+8x^2+4ax+28\\Combining\ alike\ terms\\=2x^4+ax^3-6x^3+7x^2-3ax^2+8x^2-21x+4ax+28\\= 2x^4 +(a-6)x^3+(15-3a)x^2-(21-4a)x+28\\

As it is given that

(x^2 - 3x + 4)(2x^2 +ax + 7) = 2x^4 -11x^3 +30x^2 -41x +28

In this case, co-efficient of variables will be equal, so we can compare the coefficients of x^3, x^2 or x

Comparing coefficient of x^3

a-6 = -11\\a = -11+6\\a = -5

So the value of constant a is -5

Keywords: Polynomials, factorization

Learn more about factorization at:

  • brainly.com/question/1414350
  • brainly.com/question/1430645

#LearnwithBrainly

4 0
3 years ago
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