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Naya [18.7K]
3 years ago
15

A Unites States naval submarine began at sea level. It submerged 140 ft and then traveled 40 miles. It dove down an additional 1

20 ft and traveled 25 miles. Finally it rose 29 feet. AT what depth is the submurine at?
Mathematics
2 answers:
kodGreya [7K]3 years ago
3 0

Answer: -231 ft

<u>Step-by-step explanation:</u>

The submarine started at sea level = 0

It submerged 140 ft = -140 ft

It traveled 40 miles horizontally so it is still at -140 ft

It dove down an additional 120 ft = -260 ft <em>(-140 + -120)</em>

It traveled 25 miles horizontally so it is still at -260 ft

It rose 29 ft = -231 ft <em>(-260 + 29)</em>

Note: submerged and dove are negative values and rose is positive

0 - 140 - 120 + 29 = -231

ivann1987 [24]3 years ago
3 0

Seal level would be 0.

It then submerged 140 feet so it is at -140

It then dove 120 more feet so it is now at - 260 feet.

It rose 29 feet

It is now at -231 feet. ( 231 feet below sea level)

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Substituting these values into the equation of parabola in standard form , we have

y = 3x^{2} - 2x + 2

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