Question

A Unites States naval submarine began at sea level. It submerged 140 ft and then traveled 40 miles. It dove down an additional 120 ft and traveled 25 miles. Finally it rose 29 feet. AT what depth is the submurine at?

Answer 1

Answer: -231 ft

Step-by-step explanation:

The submarine started at sea level = 0

It submerged 140 ft = -140 ft

It traveled 40 miles horizontally so it is still at -140 ft

It dove down an additional 120 ft = -260 ft (-140 + -120)

It traveled 25 miles horizontally so it is still at -260 ft

It rose 29 ft = -231 ft (-260 + 29)

Note: submerged and dove are negative values and rose is positive

0 - 140 - 120 + 29 = -231

Answer 2

Seal level would be 0.

It then submerged 140 feet so it is at -140

It then dove 120 more feet so it is now at - 260 feet.

It rose 29 feet

It is now at -231 feet. ( 231 feet below sea level)