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hjlf
2 years ago
11

I need help SOO bad Help me please!!!!!

Mathematics
2 answers:
Pepsi [2]2 years ago
7 0
Bananas is the answer following what the previos response ,it turns out being 0.6%
zlopas [31]2 years ago
6 0
60 out of 100 is 0.6% so
The answer is bananas because its the biggest percentage
You might be interested in
,,,,,....,,,,,:;,,,,,:(
pshichka [43]

start at -2 go over 2 and up 5

(-2, 5)

8 0
3 years ago
For each of the following vector fields F , decide whether it is conservative or not by computing curl F . Type in a potential f
Phantasy [73]

The key idea is that, if a vector field is conservative, then it has curl 0. Equivalently, if the curl is not 0, then the field is not conservative. But if we find that the curl is 0, that on its own doesn't mean the field is conservative.

1.

\mathrm{curl}\vec F=\dfrac{\partial(5x+10y)}{\partial x}-\dfrac{\partial(-6x+5y)}{\partial y}=5-5=0

We want to find f such that \nabla f=\vec F. This means

\dfrac{\partial f}{\partial x}=-6x+5y\implies f(x,y)=-3x^2+5xy+g(y)

\dfrac{\partial f}{\partial y}=5x+10y=5x+\dfrac{\mathrm dg}{\mathrm dy}\implies\dfrac{\mathrm dg}{\mathrm dy}=10y\implies g(y)=5y^2+C

\implies\boxed{f(x,y)=-3x^2+5xy+5y^2+C}

so \vec F is conservative.

2.

\mathrm{curl}\vec F=\left(\dfrac{\partial(-2y)}{\partial z}-\dfrac{\partial(1)}{\partial y}\right)\vec\imath+\left(\dfrac{\partial(-3x)}{\partial z}-\dfrac{\partial(1)}{\partial z}\right)\vec\jmath+\left(\dfrac{\partial(-2y)}{\partial x}-\dfrac{\partial(-3x)}{\partial y}\right)\vec k=\vec0

Then

\dfrac{\partial f}{\partial x}=-3x\implies f(x,y,z)=-\dfrac32x^2+g(y,z)

\dfrac{\partial f}{\partial y}=-2y=\dfrac{\partial g}{\partial y}\implies g(y,z)=-y^2+h(y)

\dfrac{\partial f}{\partial z}=1=\dfrac{\mathrm dh}{\mathrm dz}\implies h(z)=z+C

\implies\boxed{f(x,y,z)=-\dfrac32x^2-y^2+z+C}

so \vec F is conservative.

3.

\mathrm{curl}\vec F=\dfrac{\partial(10y-3x\cos y)}{\partial x}-\dfrac{\partial(-\sin y)}{\partial y}=-3\cos y+\cos y=-2\cos y\neq0

so \vec F is not conservative.

4.

\mathrm{curl}\vec F=\left(\dfrac{\partial(5y^2)}{\partial z}-\dfrac{\partial(5z^2)}{\partial y}\right)\vec\imath+\left(\dfrac{\partial(-3x^2)}{\partial z}-\dfrac{\partial(5z^2)}{\partial x}\right)\vec\jmath+\left(\dfrac{\partial(5y^2)}{\partial x}-\dfrac{\partial(-3x^2)}{\partial y}\right)\vec k=\vec0

Then

\dfrac{\partial f}{\partial x}=-3x^2\implies f(x,y,z)=-x^3+g(y,z)

\dfrac{\partial f}{\partial y}=5y^2=\dfrac{\partial g}{\partial y}\implies g(y,z)=\dfrac53y^3+h(z)

\dfrac{\partial f}{\partial z}=5z^2=\dfrac{\mathrm dh}{\mathrm dz}\implies h(z)=\dfrac53z^3+C

\implies\boxed{f(x,y,z)=-x^3+\dfrac53y^3+\dfrac53z^3+C}

so \vec F is conservative.

4 0
3 years ago
Which set of ordered pairs represents a function? {(-2, 4), (-1, 6), (-6, 3), (-6, 4)} {(5, 5), (9, 5), (-8, 0), (-7, 8)} {(-2,
Mademuasel [1]

The first set. It repeated 6 on the X value

5 0
2 years ago
1. Andrew ran a marathon in about 1.56 x 10^4 s. (a) Write Andrews time in standard notation. (b) Evelyn ran a marathon in 4 h a
romanna [79]

Answer:

  • (a)  15,600 s
  • (b)  Evelyn

Step-by-step explanation:

(a) 1.56×10^4 = 1.56×10000 = 15,600

(b) There are 3600 seconds in an hour, so Andrew's time was

  15600 s/(3600 s/h) = 13/3 h = 4 1/3 h

1/3 hour is 20 minutes, so Evelyn's time of 4:16 is shorter than Andrew's time of 4:20.

7 0
3 years ago
Write the number in standard form. 600,000 + 30,000 + 2,000 + 700 +70
Basile [38]
Standard form would be: 632,770
     Hope it helps!!
4 0
2 years ago
Read 2 more answers
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