The answer to 7 is 4 and the answer to 8 is 2.7
Answer:
Verify x+y+z)=(x+y)+z for the following values of x,y,z
(i)x=3/4,y=5/6,z=-7/8(
ii)x=2/; 3,y=-5/6,z=-7/9(
iii)x=3/5,y=-6/9,z=2/10(
iv)x=; - 3/5, y = - 7/10, z = - 8/15 To Verify x+(y+z)=(x+y)+z (i)x=3/4,y=5/6,z=-7/8 LHS = 3/4 + (5/6 + (-7/8)) = (3/4) + (5/6 -7/8)= (3/4) + ((20-21)/24) = 3/4 - 1/24 =(18-1)/24 = 17/24
RHS = (3/4 + 5/6) + (-7/8)= (9 + 10)/12 - 7/8 = 19/12-7/8 = (38-21)/24 = 17/24
LHS = RHS = 17/24 (ii) * x = 2/3, y = - 5/6, z = - 7/9 LHS = 2/3 + (-5/6+ (-7/9) = 2/3 + (-5/6 - 7/9) = 2/3 + (-29/18) = 2/3 - 29/18
= 12/18 - 29/18 = -17/18
RHS = (2/3 + (-5/6))+(-7/9) = (2/3 - 5/6) - 7/9 = (-1/6) - 7/9 = -1/6 - 7/9 = -3/18 - 14/18 =
-17/18
LHS = RHS....
Hence verified..
Step-by-step explanation:
hope it helps u no notebook
.???
All of them.
This is what they will turn out to be
A will end up being 2xy
B will end up being 9x^2
C will end up being 3y
D will end up being 9x^2y^4
Answer:
There are no solutions
Step-by-step explanation:
4/5 ( 20x + 5 ) = 16x - 2
Distibute on the left:
( 4/5 x 20 x ) + ( 4/5 x 5 ) = 16x - 2
16x + 4 = 16x - 2
Subtract 16x from both sides:
4=-2
Add 2 to each side:
6=0
No solutions
B. Compare independent variables
