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2 years ago

An object is moving at a speed of 7100 kilometers per minute. Express this speed in miles per second

Mathematics

1 answer:

Snowcat [4.5K]2 years ago

5 0

Answer:

73.5

Step-by-step explanation:

7100 km = 4411.735 miles 1 minute = 60 secs 4411.735/60 = 73.5 miles/sec.

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PLEASE HELP ME ASAP THIS IS DUE!!!!!!!!!!

eduard

Answer:

-8

Step-by-step explanation:

7 0

3 years ago

The vertices of quadrilateral ABCD are A(1,1), B(1,5), C(5,5), and D(7,1). You want to transform ABCD into a parallelogram by on

elixir [45]

The new coordinate of point B would have to be (-1,5). This can be seen when graphing the coordinates you gave, and by substituting 1 for -1 in the coordinates of point B into that same graph

3 0

3 years ago

The half-life of a particular element is 10 days. If you begin with 40 grams of the element write an exponential decay function

galben [10]

Answer:2.25 grams

Step-by-step explanation:

To find the remaining mass of an element, apply the following:

m0 = m/(2^n), where m0 is the remaining mass, m as the original mass and n as the number of half lives that have passed.

we have m, we just have to find n. To find n,

24/6 = 4 half lives have passed.

Applying the first formula,

m0 = (36)/(2^4) = 36/8 = 2.25 grams

Hope this helps, brainliest would be appreciated :)

4 0

2 years ago

Jenna has a round trampoline with an area of 153.86 feet squared. Jenna is 2 points

astraxan [27]

Answer:

The length of the cover that will wrap around the edge of the trampoline is 43.96 ft.

Step-by-step explanation:

Given that,

Area of trampoline, $A=153.86\ ft^2$

Jeena wants to buy a cover to put around the edge of the trampoline. We need to find the length of the cover that will wrap around the edge of the trampoline. First of all, lets find the radius of trampoline. Let is is r. So,

$\pi r^2=153.86 \\\\r=\sqrt{\dfrac{153.86 }{3.14}} \\\\r=7\ ft$

To find the length of the cover that will wrap around the edge of the trampoline we will find circumference of the trampoline as :

$C=2\pi r\\\\C=2\times 3.14\times 7\\\\C=43.96\ ft$

So, the length of the cover that will wrap around the edge of the trampoline is 43.96 ft.

7 0

3 years ago

Loto begins at his back door and walk 8 yards east, 6 yards north, 12 yards east, and 5 yards north to the barn door. About how

KonstantinChe [14]

If he could walk directly from the back door to the barn door, he would walk 10.2 yards less.

First, let's define our coordinate axis, I will use north as the y-axis and east as the x-axis.

So let's assume that Loto begins at the point (0, 0).

Then:

He moves 8 yards east, to: (8yd, 0)
He moves 6 yards north, to: (8yd, 6yd)
He moves 12 yards east, to: (20yd, 6yd)
He moves 5 yards north, to: (20yd, 11yd)

So he walked a total of 8yd + 6yd + 12yd + 5yd = 33yd

So he just moves from (0, 0) to (20yd, 11yd), thus the displacement is:

$D =\sqrt{(20yd - 0yd)^2 + (11yd - 0yd)^2} = 22.8ft$

So, if he could walk directly he would only walk 22.8 ft

The difference is:

33yd - 22.8yd = 10.2 yd.

He would walk 10.2 yards less if he could walk directly from the back door to the barn door.

If you want to learn more about displacements, you can read:

brainly.com/question/13271165

3 0

3 years ago