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3 years ago

Which real-world situation can be represented by the expression 12n – 5?

Mathematics

2 answers:

SCORPION-xisa [38]3 years ago

6 0

Answer:

D. I checked.

Step-by-step explanation:

madam [21]3 years ago

3 0

Answer:

It would be D, because you have 12 students who have tickets worth n amount, and all of them get a discount of $5.00 off. You would there have 12 times the number of tickets (n) minus $5.00 off from your discount

Step-by-step explanation:

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The complex numbers corresponding to the endpoints of one diagonal of a square drawn on a complex plane are 1 + 2i and -2 – i.

kodGreya [7K]

Technically the endpoints will be intersection of first endpoint between x=1 and y=-1second endpoint between x=-2 and y=2
so they are 1-i and -2+2i

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3 years ago

The aspect ratio of a rectangular shape is its length (L) divided by its width (W). It is expressed as L:W or L/W. If the aspect

klio [65]

Answer:21

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3 0

3 years ago

Sam rolled a die 75 times. On 39 of those rolls, he had a 6. Which statement is TRUE when the probabilities are compared?

svetlana [45]

Answer:

D)The experimental probability is greater than the theoretical probability

Step-by-step explanation:

Given:

75 times a die is rolled out of 39 times it got 6

To Find :

Which statement is true?

Solution:

The theoretical probability is given by the ,

Pt=No.of favorable outcomes/Total outcomes

Here favorable is getting 6 on the die

so how many times we can get 6 =1 time

Total outcomes =6

Pt=1/6

Pt=0.1667

Now for

The experimental Probability ,

Pe=Number times that event occur /Total no of trails

Here 39 times we get 6 and total no trails are 75

Pe=39/75

Pe=0.52

Hence we can say that Pe>Pt.

8 0

3 years ago

Read 2 more answers

Below are survival times (in days) of 13 guinea pigs that were injected with a bacterial infection in a medical study:

tresset_1 [31]

Outliers are data that are relatively far from other data elements.

The dataset has an outlier and the outlier is 120

The dataset is given as:

91 83 84 79 91 93 95 97 97 120 101 105 98

Sort the dataset in ascending order

79 83 84 91 91 93 95 97 97 98 101 105 120

<h3>The lower quartile (Q1)</h3>

The Q1 is then calculated as:

$Q1 = \frac{N +1}{4}th$

So, we have:

$Q1 = \frac{13 +1}{4}th$

$Q1 = \frac{14}{4}th$

$Q1 = 3.5th$

This is the average of the 3rd and the 4th element

$Q1 = \frac{1}{2} \times (84 + 91)$

$Q1 = 87.5$

<h3>The upper quartile (Q3)</h3>

The Q3 is then calculated as:

$Q3 = 3 \times \frac{N +1}{4}th$

So, we have:

$Q3 = 3 \times \frac{13 +1}{4}th$

$Q3 = 3 \times 3.5th$

$Q3 = 10.5th$

This is the average of the 10th and the 11th element.

$Q_3 =\frac12 \times (98 + 101)$

$Q_3 =99.5$

<h3>The interquartile range (IQR)</h3>

The IQR is then calculated as:

$IQR = Q_3 -Q_1$

$IQR = 99.5 - 87.5$

$IQR = 12$

Also, we have:

$IQR(1.5) = 12 \times 1.5$

$IQR(1.5) = 18$

<h3>The outlier range</h3>

The lower and the upper outlier range are calculated as follows:

$Lower = Q_1 - IQR(1.5)$

$Lower = 87.5- 18$

$Lower = 69.5$

$Upper = Q_3 + IQR(1.5)$

$Upper = 99.5 + 18$

$Upper = 117.5$

120 is greater than 117.5.

Hence, the dataset has an outlier and the outlier is 120