Answer:
1/10
Step-by-step explanation:
There can be 10 total digits in the tens place: 0,1,2,3,4,5,6,7,8,9
if the middle is 0 the probability is 10%
Answer:
1
Step-by-step explanation:
Probability = number of fruit type/total number of fruit. Total number of fruit = 5 + 9 + 5 = 19.
The probability of drawing an apple is P(apple) = number of apples/total number of fruit = 5/19.
The probability of drawing a peach is P(peach) = number of peaches/total number of fruit = 9/19
The probability of drawing an apple is P(orange) = number of oranges/total number of fruit = 5/19
The probability of drawing either an apple, peach or orange at the first draw of fruit from the bag is
P(apple or peach or orange) = P(apple) + P(peach) + P(orange)
= 5/19 + 9/19 + 5/19
= (5 + 9 + 5)/19
= 19/19
= 1
Answer:
x = -3
Step-by-step explanation:
Substitute -5 for p in the given equation and solve
Answer:
P(cell has at least one of the positive nickel-charged options) = 0.83.
P(a cell is not composed of a positive nickel charge greater than +3) = 0.85.
Step-by-step explanation:
It is given that the Nickel Charge Proportions found in the battery are:
0 ==> 0.17
.
+2 ==> 0.35
.
+3 ==> 0.33
.
+4 ==> 0.15.
The numbers associated to the charge are actually the probabilities of the charges because nickel is an element that has multiple oxidation states that is usually found in the above mentioned states.
a) P(cell has at least one of the positive nickel-charged options) = P(a cell has +2 nickel-charged options) + P(a cell has +3 nickel-charged options) + P(a cell has +4 nickel-charged options) = 0.35 + 0.33 + 0.15 = 0.83.
Or:
P(a cell has at least one of the positive nickel-charged options) = 1 - P(a cell has 0 nickel-charged options) = 1 - 0.17 = 0.83.
b) P(a cell is not composed of a positive nickel charge greater than +3) = 1 - P(a cell is composed of a positive nickel charge greater than +3)
= 1 - P(a cell has +4 nickel-charged options) '.' because +4 is only positive nickel charge greater than +3
= 1 - 0.15
= 0.85
To summarize:
P(cell has at least one of the positive nickel-charged options) = 0.83!!!
P(a cell is not composed of a positive nickel charge greater than +3) = 0.85!!!
