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kirill [66]
3 years ago
12

What is the equation of the following graph

Mathematics
1 answer:
MrRa [10]3 years ago
5 0

on the very far left it says (5,-1.5)

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2 1⁄2 ÷ 1 3⁄6 please help me with the RIGHT answer.
ycow [4]

Answer:

1\frac{2}{3}

Step-by-step explanation:

We want to simplify:

2 \frac{1}{2}  \div 1 \frac{3}{6}

This is the same as:

2 \frac{1}{2}  \div 1 \frac{1}{2}

Now let us convert the mixed numbers to improper fractions.

\frac{5}{2}  \div  \frac{3}{2}

We multiply by the reciprocal of the second fraction to get:

\frac{5}{2}  \times  \frac{2}{3}

Cancel out the common factors to obtain:

\frac{5}{3}  = 1 \frac{2}{3}

5 0
3 years ago
Find the sum of the prime numbers that are between 12 and 42.
Zielflug [23.3K]

Answer:

<h2>210</h2>

Step-by-step explanation:

list of prime #s between 12 and 42:

13, 17, 19, 23, 29, 31, 37, 41

now add them up:

13+17+<em>19</em>+<u>23</u>+<em>29+31</em>+<u>37</u>+<em>41</em>

30+60+60+60

90+120

210

3 0
3 years ago
Read 2 more answers
Can someone please help me I’m desperate it due tomorrowwww
zlopas [31]

Answer:

Step-by-step explanation:

First box: m=1/2

Second box: m=2

Third box: m=1

Fourth box: m=2

5 0
3 years ago
Select the equations of f the lines that are parallel to the lines whose equations is y=3x+5
saw5 [17]

Answer:

<h2>y = 3x + b where b is any real number</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept

We have the equation: y=3x+5

Parallel lines have the same slope. Therefore the equation of the lines that are parallel to the given line if in form:

y=3x+b

where b is any real number.

5 0
3 years ago
PLS HELP WILL GIVE BRANLIEST
AnnZ [28]

Answer:

she took 13 classes that were worth 3 credits

Step-by-step explanation:

well we know that some of the classes are worth 3 and some are worth 4 and that all of these together = 59 so your first equation would be

3x+4y=59

x  would be the number of classes worth 3 credits and y would be the number of classes worth 4 credits.

then it says the total number of classes that they took was 18 so we know that

x + y =18.

you want to solve for the number of 3 credit classes so lets go ahead and get rid of the y values. SO you need you multiply the x+y equation by 4

4x+4y=72

then subtract 4x+4y=72  from 3x+4y=59 to get

-x = -13

and then x is a negative so you need to divide -1 from both sides and you get that she took 13 classes that were worth 3 credits.

3 0
2 years ago
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