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3 years ago

Find the values of a and b such that x^2-4x+9=(x+a)^2+b

Mathematics

1 answer:

m_a_m_a [10]3 years ago

6 0

Answer:

a = -2

b = 5

Step-by-step explanation:

We can identify the right side of the equation as completing the square. So, we simply complete the square for x² - 4x + 9 to find our answer,

Step 1: Isolate xs

x² - 4x = -9

Step 2: Complete the square

x² - 4x + 4 = -9 + 4

(x - 2)² = -5

Step 3: Move -5 over

(x - 2)² + 5

And we have our answer!

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Gregory runs at a steady pace on his treadmill. In 2 hours, he runs 12 miles. The graph represents this situation. Which point w

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How much is 1/9 of 3/8 (in lowest terms)? A)4/17 B)03/17 C)1/36 D)1/24

mojhsa [17]

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1/24

Step-by-step explanation:

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2 years ago

A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute

nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

$P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}$

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

$P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301$

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

$P(k\geq8)=1-P(k$

$P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\$

$P(k$

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

$P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002$

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3 years ago

The sequence 2,6,18,54 shows the number of sit-ups Alan can do each day.

jek_recluse [69]

Step-by-step explanation:

this sequence is geometric not arithmetic

HOw we know that ??

when we get a common difference that must Be equal

d=6-2=4 not equal to d=18-6=12

So it is not arithmetic

but when we get the common ratio that also must be equal

r=6/2=18/6=54/18=3 equal

So it is geometric

By using this equation:

a(n)=a(1)*r^(n-1)

and we have a(1)=2 , r=3

Explicit rule: a(n)=2*(3)^(n-1)

Recursive rule: a(n)= r * a(n-1)

a(n-1) ⇒ priviuse term

SO: a(n)= 3 * a(n-1)

For example:

a(3)= 3 * 6 =18

I really hope this helps <3

7 0

3 years ago