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2 years ago

Find the values of a and b such that x^2-4x+9=(x+a)^2+b

Mathematics

1 answer:

m_a_m_a [10]2 years ago

6 0

Answer:

a = -2

b = 5

Step-by-step explanation:

We can identify the right side of the equation as completing the square. So, we simply complete the square for x² - 4x + 9 to find our answer,

Step 1: Isolate xs

x² - 4x = -9

Step 2: Complete the square

x² - 4x + 4 = -9 + 4

(x - 2)² = -5

Step 3: Move -5 over

(x - 2)² + 5

And we have our answer!

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Find side x , give your answer 1 decimal place

Vladimir [108]

Given:

Let A denote the angle of the given triangle which measures ∠A = 81°

Let B denote the angle which measures ∠B = 40°

The length of the side a = x.

The length of the side b = 7 cm.

We need to determine the value of x.

Value of x:

The value of x can be determined using the law of sine formula.

Applying the law of sine, we have;

$\frac{sin \ A}{a}=\frac{sin \ B}{b}$

Substituting the values, we have;

$\frac{sin \ 81^{\circ}}{x}=\frac{sin \ 40^{\circ}}{7}$

Simplifying, we get;

$\frac{0.988}{x}=\frac{0.643}{7}$

Cross multiplying, we have;

$0.988 \times 7=0.643 x$

$6.916=0.643x$

$10.8=x$

Thus, the length of the side x is 10.8 cm.

4 0

2 years ago

Select all factors of the expression 6x2 – 140 – 40

Romashka [77]

Answer:

is their answer choices

5 0

2 years ago

Five divided by two multiplied by six

max2010maxim [7]

I think the answer is 15, because 5 divided by 2 is 2.5. 2.5 times 6 is 15

5 0

2 years ago

Read 2 more answers

An electric sale gives a reading equal to the true weight plus a random error that isnormally distributed with mean 0 and standa

Pepsi [2]

Answer:

a) 95% confidence interval estimate of the true weight is (3.026, 3.274)

b) 99% confidence interval estimate of the true weight is (2.944, 3.356)

Step-by-step explanation:

Confidence Interval can be calculated using M±ME where

M is the mean of five successive weightings (3.150)

ME is the margin of error from the mean

And margin of error (ME) can be calculated using the formula

ME= $\frac{t*s}{\sqrt{N} }$ where

t is the corresponding statistic in the given confidence level and degrees of freedom(t-score)

s is the standard deviation of the random error (0.1)

N is the sample size (5)

Using the numbers 95% confidence interval estimate of the true weight is:

3.150± $\frac{2.776*0.1}{\sqrt{5} }$ ≈3.150±0.124

And 99% confidence interval estimate of the true weight is:

3.150± $\frac{4.604*0.1}{\sqrt{5} }$ ≈3.150±0.206

3 0

3 years ago

PLEASE HELP ILL GIVE BRAINLYIST

Vera_Pavlovna [14]

Answer:

Alright this is complecated but I think you can go on this other math website symbolab there will be a tutor and answer it in 15-30 minuted it helps!

Step-by-step explanation:

5 0

2 years ago