1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Likurg_2 [28]
3 years ago
7

Solve for x. 0 < 3x - 6 s 18 0 2 x<0 or x >8 x<2 or x > 8

Mathematics
1 answer:
docker41 [41]3 years ago
4 0

Answer:

Step-by-step explanation:

You might be interested in
You randomly guess the answers to two questions on a multiple-choice test. Each question has three choices: A, B, and C.
Fantom [35]

Answer: pick a bc its the first lettr of the alphebet

4 0
3 years ago
An unknown number y is 12 more than an unknown number x. The number y is also x less than 17. The equations to find x and y are
grandymaker [24]

Answer:

d because then you can solve for y then use your answer to find x

4 0
3 years ago
Read 2 more answers
Which of the following bank reconciliation items would be reflected in a journal entry?
Len [333]
C. Bank service charges
7 0
3 years ago
Read 2 more answers
Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o
kirza4 [7]

Answer:

a) H0: \sigma = 1.34

H1: \sigma \neq 1.34

b) df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

c) t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

\sigma_o =1.34 the value that we want to test

p_v represent the p value for the test

t represent the statistic  (chi square test)

\alpha=0.01 significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: \sigma = 1.34

H1: \sigma \neq 1.34

The statistic is given by:

t=(n-1) [\frac{s}{\sigma_o}]^2

Part b

The degrees of freedom are given by:

df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

Part c

Replacing the info we got:

t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0
3 years ago
Can somebody please tell me if it’s right? i’ll mark u the brainliest
Nastasia [14]

Answer:

Yes, you are correct.

Step-by-step explanation:

You are substituting the measure of angle x as the measure of angle a since they are congruent to each other.

8 0
3 years ago
Other questions:
  • -8 -5 + 9h - 2f using h = 7 and f =9 ?
    9·1 answer
  • 2x^2-7x+6
    13·2 answers
  • What is the radius <br> (x + 10)² + (y - 8)2 = 169
    10·1 answer
  • HELP PLZ<br> ASAP thanks!
    7·1 answer
  • Rounding<br>Round each number to the nearest hundred<br>7892<br>472​
    11·2 answers
  • What is the value of x?
    15·2 answers
  • Can someone help me?
    6·2 answers
  • Define least common multiple
    6·2 answers
  • -5s=−13<br> solve for s .
    15·1 answer
  • What is the answer to this question
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!