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sweet-ann [11.9K]
2 years ago
7

A new club sent out 294 coupons to boost sales for next year's memberships. They provided 6 times as many to potential members t

han to existing members. How many coupons did they send to existing members?
Mathematics
2 answers:
baherus [9]2 years ago
6 0

Answer:

42

Step-by-step explanation:

6 times as many means that they sent out 6 to 1. Anytime I see x times as many i always add 1. The formula for this would be x+1. x=6 6+1=7. There were 294 coupons sent out so 294/7=42. 42 equals the amount of existing members there are. I hope you understand.

andriy [413]2 years ago
3 0
The answer to this equation is 42 coupons.


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7 0
2 years ago
The figure shown models a roof truss. Based on the markings, is there enough information to prove that ΔACD ≅ ΔBCD?
Daniel [21]

Answer:

C

Step-by-step explanation:

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2 years ago
Solve the equation and check the solution.
777dan777 [17]

Answer:

a = 4

Step-by-step explanation:

Here, we want to write and solve the given equation

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This is correct

7 0
3 years ago
Read 2 more answers
Write an equation for an exponential growth function where the initial population is 74 and the population quadruples during eac
Liono4ka [1.6K]
If the population quadruples every period say hour, that means the "rate of growth" is 300%, so whatever the current amount, increased by 3 times as much is 4 times the current amount, or a quadrupled amount.

\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &74\\
r=rate\to 300\%\to \frac{300}{100}\to &3.00\\
t=\textit{elapsed time}\\
\end{cases}
\\\\\\
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6 0
3 years ago
The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented
leva [86]

The equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: \frac{x^{2}}{a^{2}}  - \frac{y^{2}}{b^{2}}    = 1

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

Now if the distance from center to the directrix line is 'd', then

d= \frac{a^{2}}{c}

Here the directrix line is given as : x= 2304/50

Thus, \frac{a^{2}}{c}  = \frac{2304}{50}

⇒ \frac{a^{2}}{50}  = \frac{2304}{50}

⇒ a² = 2304

⇒ a = √2304 = 48

For hyperbola, b² = c² - a²

⇒ b² = 50² - 48² (By plugging c=50 and a = 48)

⇒ b² = 2500 - 2304

⇒ b² = 196

⇒ b = √196 = 14

So, the equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

5 0
3 years ago
Read 2 more answers
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