Answer:

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

And we can solve for
and solving we got:

And from the previous result we got:

And solving we got:

And then we can find the mean with this formula:

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0
Step-by-step explanation:
For this case we know that the currently mean is 2.8 and is given by:

Where
represent the number of credits and
the grade for each subject. From this case we can find the following sum:

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

And we can solve for
and solving we got:

And from the previous result we got:

And solving we got:

And then we can find the mean with this formula:

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0
Answer:
Step-by-step explanation:
Find the sum of the squares of the residuals for
y 2x 6
Answer: 96 games
Step-by-step explanation:
32 total possibilities
3 people
32*3= 96
Answer:
x=y+3
Step-by-step explanation:
you just swap variables.
Answer:
1.) 112.5 degrees
2.) 67.5 degrees
3.) 150 degrees
4.) 240 degrees
5.) 540 degrees
( don't hate me if any is wrong don't think they are but just trying to help) let me know if any of them are wrong and if it helped!