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Dima020 [189]
3 years ago
11

A dealer sold 200 tennis racquets. Some were sold for $33 each, and the rest were sold on sale for $18. The total receipts form

these sales were 4.800. How many racquets did the dealer sell at $18 each.
Mathematics
1 answer:
Mumz [18]3 years ago
6 0

120 tennis racquets were sold for $ 18 each

<em><u>Solution:</u></em>

Let x = number that sell for $18 each

Then, 200 - x = number that sell for $33 each

<em><u>The total receipts form these sales were 4800 dollars</u></em>

Thus we frame a equation as:

number that sell for $18 each x 18 + number that sell for $33 each x 33 = 4800

x \times 18 + (200-x) \times 33 = 4800\\\\Solve\ the\ above\ equation\ for\ x\\\\18x + 6600 - 33x = 4800\\\\Move\ the\ variables\ to\ one\ side\\\\18x-33x = 4800-6600\\\\-15x = -1800\\\\Divide\ both\ sides\ of\ equation\ by\ -15\\\\x = 120

Thus 120 tennis racquets were sold for $ 18 each

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