All categories

3 years ago

the scale of a map is 1 cm: 75 km what is the actual distance between two towns that are 3 cm apart on the map?

Mathematics

2 answers:

Juliette [100K]3 years ago

4 0

Answer:fghfhrfhghggghf

Step-by-step explanation:

UkoKoshka [18]3 years ago

4 0

Answer:

The distance between the two towns is 225 km.

Step-by-step explanation:

We are given the following information in the question:

The scale of map is:

$1\text{ cm}:75\text{ km}$

This means that a distance of 1 cm on map marks a distance of 75 km in reality,

We have to find the distance between two towns.

Distance between two towns on the map = 3 cm

Distance between towns =

We could use the concept of ratio to solve this problem:

$\displaystyle\frac{1}{75} = \frac{3}{d}\\\\\text{whered is the distance between the two towns}\\\Rightarrow d = 3\times 75 = 225$

Hence, the distance between the two towns is 225 km.

You might be interested in

58 = 7/4x well, basically I am really bad with fractions, and I'm supposed to do this on a computer, I don't have a calculator I

KiRa [710]

58=7/4x
Multiply both sides by 4 so the fraction cancels out:
232=7x
Divide both sides by 7:
x=33.14 (rounded)

Hope this helps :)

4 0

3 years ago

I neeeed helppppppp pleaseeee

Artist 52 [7]

Answer: 6144m^2

Step-by-step explanation:

4 0

3 years ago

Which number is a solution for the inequality below?

nasty-shy [4]

Answer:

D 90

Step-by-step explanation:

x/4 ≥ 20

Multiply each side by 4

4*x/4 ≥ 20*4

x ≥ 80

The only number greater than or equal to 80 is 90

7 0

3 years ago

Read 2 more answers

What is the best approximation of the length of segment QS? (Note: cos 80° = 0.17)

matrenka [14]

Answer: $QS=11.8cm$

Step-by-step explanation:

1. You have the following information:

- The lenght of $RS$ is 2 centimeters.

- The angle m∠S=80°.

- Cos80°=0.17

2. Therefore, you can calculate the lenght of the segment $QS$ as following:

$cos80=\frac{adjacent}{hypotenuse}$

$adjacent=2cm\\hypotenuse=QS\\cos80=0.17$

3. Substitute values and solve for $QS$ :

$0.17=\frac{2cm}{QS}\\QS=\frac{2cm}{0.17} \\QS=11.76cm$

4. To the nearest tenth:

$QS=11.8cm$

6 0

3 years ago

Working alone Ryan can dig a 10ft by 10ft hole in five hours castel can dig the same same hole in six how long would it take the

Sergeeva-Olga [200]

Answer:

The time taken by both when they work together is 2 hours 42 minutes .

Step-by-step explanation:

Given as :

The time taken by Ryan to dig 10 ft by 10 ft hole = x = 5 hours

The time taken bu Castel to dig 10 ft by 10 ft hole = y = 6 hours

Let The time taken by both when they work together = z hours

<u>According to question</u>

The time taken by both when they work together = time taken by Ryan to dig 10 ft by 10 ft hole + time taken bu Castel to dig 10 ft by 10 ft hole

i.e $\dfrac{1}{z}$ = $\dfrac{1}{x}$ + $\dfrac{1}{y}$

Or, $\dfrac{1}{z}$ = $\dfrac{1}{5}$ + $\dfrac{1}{6}$

<u>Taking LCM</u>

Or, $\dfrac{1}{z}$ = $\dfrac{6 + 5}{30}$

Or, $\dfrac{1}{z}$ = $\dfrac{11}{30}$

Or, z = $\dfrac{30}{11}$ hours

∴ z = 2 hours 42 minutes

So, The time taken by both when they work together = z = 2 hours 42 min

Hence, The time taken by both when they work together is 2 hours 42 minutes . Answer

3 0

3 years ago