The Lewis family and the Perry family each used their sprinklers last summer. The water output rate for the Lewis family's sprinkler was 15 L per hour. The water output rate for the Perry family's sprinkler was 40 L per hour. The families used their sprinklers for a combined total of 65 hours, resulting in a total water output of 1850 L . How long was each sprinkler used
Answer:
Hours of use of sprinkler by Lewis family is 30 hours.
Hours of use of sprinkler by Perry family is 35 hours.
Step-by-step explanation:
Let W = hours of use by Lewis family
65 - W = hours of use by Perry family
Then;
15W + 40*(65 - W) = 1850
15W + 2600 - 40W = 1850
(15 - 40)W = 1850 - 2600
-25W = −750
W = 750/25 = 30
Therefore;
W = 30
65 - W = 65 - 30 = 35
Hence,
Hours of use by Lewis family is 30 hours.
Hours of use by Perry family is 35 hours.
Answer:
2.5
Step-by-step explanation:
Answer:

And we can assume a normal distribution and then we can solve the problem with the z score formula given by:

And replacing we got:


We can find the probability of interest using the normal standard table and with the following difference:

Step-by-step explanation:
Let X the random variable who represent the expense and we assume the following parameters:

And for this case we want to find the percent of his expense between 38.6 and 57.8 so we want this probability:

And we can assume a normal distribution and then we can solve the problem with the z score formula given by:

And replacing we got:


We can find the probability of interest using the normal standard table and with the following difference:

Answer:
B) 4x-5-3x=x+5 has no solution.
Step-by-step explanation:
A) 4x+4=4-4x
4x-(-4x)+4=4
4x+4x+4=4
8x+4=4
8x=4-4
8x=0
x=0/8
x=0
------------------
B) 4x-5-3x=x+5
4x-3x-5=x+5
x-5=x+5
x-x-5=5
-5=5
no solution.
------------------------
C) 4x+15-9x=5x+15
4x-9x+15=5x+15
-5x+15=5x+15
-5x-5x+15=15
-10x+15=15
-10x=15-15
-10x=0
x=0/-10
x=0
------------------------
D) 4x+2-x=4+3x-2
3x+2=3x+4-2
3x+2=3x+2
infinitely many solutions.