This is a strange question, and f(x) may not even exist. Why do I say that? Well..
[1] We know that f(a+b) = f(a) + f(b). Therefore, f(0+0) = f(0) + f(0). In other words, f(0) = f(0) + f(0). Subtracting, we see, f(0) - f(0) = f(0) or 0 = f(0).
[2] So, what's the problem? We found the answer, f(0) = 0, right? Maybe, but the second rule says that f(x) is always positive. However, f(0) = 0 is not positive!
Since there is a contradiction, we must either conclude that the single value f(0) does not exist, or that the entire function f(x) does not exist.
To fix this, we could instead say that "f(x) is always nonnegative" and then we would be safe.
<span>A
football team lost 5 yards on each 3 plays.
Let’s use a number line to be able to see how far in the field did they lost in
3 games.
=> 1 : 5 (1 game is to 5 yards)
=> 3 : 15 (3 games is to 15 yards )
All in all they lost 15 yards in 3 games.
pls. see attachment for more presentation.</span>
Raphael works 12 hours each week. He earns £4 per hour. Tom saves 1/3 of earnings each week. How many weeks does it take Tom to save £80?
5 weeks
Answer:
243,746,778
or 243 million 746 thousand 778
Hope the answer helps!
Step-by-step explanation: