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2 years ago

Please help!!! I don't know how to do this

Mathematics

1 answer:

saveliy_v [14]2 years ago

5 0

Answer:

domain = all real numbers

Step-by-step explanation:

domain is the x axis

its asking what it goes to but if they have arrows then forever

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Find 38% of the number 405. a. 153.9% c. 1065.79 b. 153.9 d. 15,390

vredina [299]

A.) 153.9 would be your answer!

3 0

3 years ago

A baseball team has home games on Friday and Sunday. The two games together earn $3432.00 for the team. Friday's game generate

scoundrel [369]

Answer:

Friday's game generates $1,664 while Sunday's, game generates $1,768 for a total of $3432.00.

Step-by-step explanation:

First, identify what you know:

1) A baseball team has home games on Friday and Sunday

2) Both games, combined, earned $3432.00

3) Friday's game generated $104.00 less than Sunday's game.

We can create a formula to solve our problem!

$3,432 = x + (x - 104)

$3,432 + 104 = x + x

$3,536 = 2x

$3,536/2 = x

x = $1,768

Sunday's game earned $1,768! If Friday's game earned $104 less, then simply subtract that from Sunday's earning!

$1,768 - $104 = $1,664

Friday's game cost $1,664, and Sunday's game earned $1,768!

Hope this helps! :)

7 0

3 years ago

Read 2 more answers

I just need the answer please! ! !

OLEGan [10]

The first one x>7 nsdnejsjdhwkakns stupid 20 characters

3 0

2 years ago

Create the equation of a quadratic function with a vertex of (5,6) and a y-intercept of -69

Elena L [17]

If the y-intercept is at -69, meaning the point is (0, -69), thus x = 0, y = -69

$\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
\boxed{y=a(x- h)^2+ k}\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------\\\\
vertex~(5,6)\quad 
\begin{cases}
x=5\\
y=6
\end{cases}\implies y=a(x-5)^2+6
\\\\\\
\textit{we also know that }
\begin{cases}
x=0\\
y=-69
\end{cases}\implies -69=a(0-5)^2+6
\\\\\\
-75=25a\implies \cfrac{-75}{25}=a\implies a=-3
\\\\\\
therefore\qquad \boxed{y=-3(x-5)^2+6}$

3 0

2 years ago

I need help with prob #2 on this

Aleks [24]

Answer:

x and y are not in direct variation.

Step-by-step explanation:

Direct Variation

Two variables x and y have a direct proportion or variation if:

y = k.x

Where k is the factor of proportionality. The value of k must be constant for every ordered pair (x,y). If only one of them does not have the very same k, then the relationship is not direct.

The value of k can be solved from the equation:

$\displastyle k=\frac{y}{x}$