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Genrish500 [490]
3 years ago
7

What are the domain and range of f(x) = 2(3^x)?

Mathematics
1 answer:
solong [7]3 years ago
4 0

Answer:

Step-by-step explanation:

no x-intercept/zero

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What is the probability of drawing the compliment of a king or a
inna [77]

Answer:

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards = 0.846

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Let 'S' be the sample space associated with the drawing of a card

n (S) = 52C₁ = 52

Let E₁ be the event of the card drawn being a king

n( E_{1} ) = 4 _{C_{1} }  = 4

Let E₂ be the event of the card drawn being a queen

n( E_{2} ) = 4 _{C_{1} }  = 4

But E₁ and E₂ are mutually exclusive events

since E₁ U E₂ is the event of drawing a king or a queen

<u><em>step(ii):-</em></u>

The probability  of drawing of a king or a  queen from a standard deck of playing cards

P( E₁ U E₂ ) = P(E₁) +P(E₂)

                 = \frac{4}{52} + \frac{4}{52}

P( E₁ U E₂ ) = \frac{8}{52}

<u><em>step(iii):-</em></u>

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards

P(E_{1}UE_{2})  ^{-} = 1- P(E_{1} U E_{2} )

P(E_{1}UE_{2})  ^{-} = 1- \frac{8}{52}

P(E_{1}UE_{2})  ^{-} = \frac{52-8}{52} = \frac{44}{52} = 0.846

<u><em>Conclusion</em></u>:-

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards = 0.846

5 0
3 years ago
Thirty-five sophomores, 69 juniors and 24 seniors are randomly selected from 461 sophomores, 328 juniors and 558 seniors at a ce
LekaFEV [45]

Answer:

Stratified sampling technique(A)

Step-by-step explanation:

From the question, the population of an high school from which selection was made equals 461 sophomores, 328 juniors and 558 seniors.

35 sophomores, 69 juniors and 24 seniors are randomly selected. The technique used in selecting is Stratified sampling technique. This is because stratified sampling involves dividing the entire population into stratas and then selects a final sample randomly from the different strata. This means that a smaller part of the entire population is used as a sample in drawing conclusions for the entire population.

7 0
3 years ago
Determine dois números ímpares consecutivo cujo produto seja 195
miv72 [106K]
Let 1st integer  = xLet 2nd integer = x + 1 We set up an equation. x(x + 1) = 195 x2 + x = 195 x2 + x - 195 = 0

We will use the quadratic formula: x = (-b ± √(b2 - 4ac) / (2a) x = (-1 ± √(1 - 4(-195))) / 2 x = (-1 ± √(781)) / 2 x = (-1 ± 27.95) / 2 x = 13.48x = -14.78 
<span>We determine which value of x when substituted gives us a product of 195.</span> 13.48(14.48) = 195.19-14.48(-13.48) = 195.19 <span>The solution is 2 sets of two consecutive number</span> <span>Set 1</span> The 1st consecutive integer is 13.48The 2nd consecutive integer is 14.48 
<span>Set 2</span> The 1st consecutive integer is -14.48The 2nd consecutive integer is -13.48Hopefully this helped, hard work lol :)
8 0
3 years ago
A ball is launched from a 682.276 meter tall platform. the equation for the ball's height h at time t seconds after launch is h(
blagie [28]

The maximum height the ball achieves before landing is 682.276 meters at t = 0.

<h3>What are maxima and minima?</h3>

Maxima and minima of a function are the extreme within the range, in other words, the maximum value of a function at a certain point is called maxima and the minimum value of a function at a certain point is called minima.

We have a function:

h(t) = -4.9t² + 682.276

Which represents the ball's height h at time t seconds.

To find the maximum height first find the first derivative of the function and equate it to zero

h'(t) = -9.8t = 0

t = 0

Find second derivative:

h''(t) = -9.8

At t = 0; h''(0) < 0 which means at t = 0 the function will be maximum.

Maximum height at t = 0:

h(0) = 682.276 meters

Thus, the maximum height the ball achieves before landing is 682.276 meters at t = 0.

Learn more about the maxima and minima here:

brainly.com/question/6422517

#SPJ1

4 0
1 year ago
erica watch 1/2 of a movie in the morning and she watched some at night and by the end of the day she still had 1/3 of left how
Anastaziya [24]
Convert to equivalent fractions to see
Both bottom s can be 6
So times the half by 3
And times the third by 2
1/2=3/6
1/3=2/6
So she has a total of 5/6 of the movie accounted for...
So the left over is 1/6
1/6 at nighttime
8 0
3 years ago
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