Answer:
First to find AB we use cosine
cos ∅ = Adjacent / hypotenuse
AB is the adjacent
BC is the hypotenuse
cos ∅ = AB/AC
cos 70 = AB / 8
AB = 8 cos 70°
AB = 2.736
AB = 2.7cm to one decimal place
Hope this helps
Here we have a relatively basic trigonometry problem using a right triangle.
We are looking to calculate the value of the side OPPOSITE to our given angle of 36 degrees. We are given the length of the side ADJACENT to this angle. Using this knowledge, we must first determine what trigonometric ratio we need to use.
For the purpose of answering this question, I will label the angle of 36 degrees angle A.
Because of the values we have been given, the best ratio to use would be:
sin(A) = opposite/hypotenuse
So, if we plug in our known and unknown values, we end up with:
sin(36) = x / 11
To find x, we must first try and get x on one side of the equation, so I am going to do that by multiplying both sides by 11, giving us this equation:
11 × sin(36) = x
Next, multiply (( 11 × sin(36) )), and this will give you the value the length of side X.
So, your answer should end up as 6.5 if we round the decimal.
Answer:
The weight of cat is <u>14 pounds</u> and the weight of kitten is <u>4 pounds</u>.
Step-by-step explanation:
Given:
Callie has a new kitten. It can weigh 3 pounds less than half the weight of Callie‘s cat. Together the cat and kitten weigh 18 pounds.
Now, to find the weight of each animal:
Let the cat's weight be 
And the kitten weight = 
Total weight of cat and kitten = 18 pounds.
Now, to set an equation to get the weight of each animal:
<em>Multiplying both sides by 2 we get:</em>
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<em>Adding both sides by 6 we get:</em>
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<em>Dividing both sides by 3 we get:</em>
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<em>The weight of cat = 14 pounds.</em>
Substituting the value of 
to get the kitten's weight:
<em>The kitten's weight = 4 pounds.</em>
Therefore, the weight of cat is 14 pounds and the weight of kitten is 4 pounds.
Step-by-step explanation:
Use the method for solving Bernoulli equations to solve the following differential equation.
StartFraction dy Over dx EndFraction plus StartFraction y Over x minus 9 EndFraction equals 5 (x minus 9 )y Superscript one half
