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yuradex [85]
3 years ago
12

Given the equation 6(8g + 2) + 45 = 153, write a scenario similar to Parts A and B

Mathematics
2 answers:
Zanzabum3 years ago
5 0

Answer:

Step-by-step explanation:

6(8g+2)+45=153

48g+12+45=153

48g+57=153

48g=153-57

48g=96

g=96÷48

g=2

Semenov [28]3 years ago
4 0

Answer:

6(8g + 2) + 45 = 153

48g + 12 + 45 = 153

48g +  57 = 153

<u>        - 57     - 57</u>

<u>48g = 96</u>

     48

g = 2

each family bowled 2 games.

Step-by-step explanation:

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A train left a station at 8:13 a.m. arriving at its destination at 4:52 p.m. If the stations are 527.65 miles apart, calculate t
Tomtit [17]

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Answer:

  D.  61 mi/h

Step-by-step explanation:

The travel time is 16:52 -8:13 = 8:39 hours, or 8.65 hours. Then the speed is ...

 speed = distance/time = 527.65 mi/(8.65 h) = 61 mi/h

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<em>Additional comment</em>

It is often convenient to use "military" or "24-hour" time for calculations of time periods that extend over noon or midnight. For this purpose, 12 gets added to the hour number in the afternoon (pm). Of course, 39 minutes is 39/60 hours. That is found to be 0.65 hours by performing the division of 39 by 60.

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In a game you have 1/20 probability of winning $76 and a 19/20 probability of losing $9. What is your expected value?
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Answer:

1

Step-by-step explanation:

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How to solve for y if  the equation is y=5/2x + 5 if x is zero
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y=\dfrac{5}{2}\cdot0+5\\&#10;y=0+5\\&#10;y=5
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Ill give you Brainlyest! I need help ASAP work shown, please!!<br> problems 8-15
8_murik_8 [283]

Using the segment addition theorem, the solutions are:

5. x = 17

6. x = 7

7. x = 14

BC = 27

CD = 61

BD = 88

8. AB = 26

9. LJ = 46

10. x = 3

11. FG = 15

12. QS = 34

13. BC = 26

14. EG = 19

15. QS = 68

<h3>How to Apply the Segment Addition Theorem?</h3>

The segment addition theorem would be used to solve the problems as shown below:

5. UW = UV + VW [segment addition theorem]

Substitute

6x - 35 = 19 + 4x - 20

6x - 4x = 35 + 19 - 20

2x = 34

x = 17

6. HJ = HI + IJ [segment addition theorem]

Substitute

7x - 27 = 3x - 5 + x - 1

7x - 3x - x = 27 - 5 - 1

3x = 21

x = 7

7. BD = BC + CD [segment addition theorem]

Substitute

7x - 10 = 4x - 29 + 5x - 9

7x - 4x - 5x = 10 - 29 - 9

-2x = -28

x = 14

BC = 4x - 29 = 4(14) - 29 = 27

CD = 5x - 9 = 5(14) - 9 = 61

BD = 7x - 10 = 7(14) - 10 = 88

8. BC = BD

Substitute

2x + 1 = 5x - 26

2x - 5x = -1 - 26

-3x = -27

x = 9

AB = 43 - BC

AB = 43 - 2x + 1 = 43 - 2(9) + 1 = 26

9. 7x - 10 = 9x - 11 - (x + 3)

7x - 10 = 9x - 11 - x - 3

7x - 9x + x = 10 - 11 - 3

-x = -4

x = 4

LJ = 28 + 7x - 10 = 28 + 7(4) - 10

LJ = 46

10. 8x + 11 = 12x - 1

8x - 12x = -11 - 1

-4x = -12

x = 3

11. 11x - 7 = 3x + 9

11x - 3x = 7 + 9

8x = 16

x = 2

FG = 11x - 7 = 11(2) - 7

FG = 15

12. 5x - 3 = 21 - x

5x + x = 21 + 3

6x = 24

x = 4

QS = 2(5x - 3) = 10x - 6 = 10(4) - 6

QS = 34

13. 8x - 20 = 2(3x - 1)

8x - 20 = 6x - 2

8x - 6x = 20 - 2

2x = 18

x = 9

BC = AB = 3x - 1 = 3(9) - 1

BC = 26

14. 5x - 1 = 7x - 13

5x - 7x = 1 - 13

-2x = -12

x = 6

EG = 6x - 4 - 13 = 6(6) - 4 - 13

EG = 19

15. RT - ST = RS

Substitute

8x - 43 - (4x - 1) = 2x - 4

8x - 43 - 4x + 1 = 2x - 4

4x - 42 = 2x - 4

4x - 2x = 42 - 4

2x = 38

x = 19

QS = 2(RS)

QS = 2(2x - 4) = 4x - 8 = 4(19) - 8

QS = 68

Learn more about the segment addition theorem on:

brainly.com/question/28263183

#SPJ1

8 0
1 year ago
What is 8/11 - 7/11 in simplest form
NARA [144]

Answer:

It is 1/11

Step-by-step explanation:

Apply the rule a/c +- b/c = a+-b/c

=8-7/11

=1/11

8 0
3 years ago
Read 2 more answers
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