(4x3+2x+6)+(2x3-x2+2)
Final result :
6x3 - x2 + 2x + 8
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "x2" was replaced by "x^2". 2 more similar replacement(s).
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(((4•(x3))+2x)+6)+((2x3-x2)+2)
Step 2 :
Equation at the end of step 2 :
((22x3 + 2x) + 6) + (2x3 - x2 + 2)
Step 3 :
Checking for a perfect cube :
3.1 6x3-x2+2x+8 is not a perfect cube
Trying to factor by pulling out :
3.2 Factoring: 6x3-x2+2x+8
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 2x+8
Group 2: 6x3-x2
Pull out from each group separately :
Group 1: (x+4) • (2)
Group 2: (6x-1) • (x2)
Those are 185, 186 and 187
What you do is create this system of equations:
x+y+z=558 (three integers add up to 558)
x+1=y (they are consecutive, so that is translated as a number+1)
y+1=z (same logic as before)
And then you just resolve that system.
4x + y = 5
3x + y = 8
y = -3x + 8
4x +(-3x + 8) = 5
4x -3x + 8 = 5
x + 8 = 5
x = -3
y = -3(-3) + 8
y = -9 + 8
y = -1
Slope formula: m = 
(Knowing that m represents the slope)
Substitute (1,0) for (x1,y1), and (-1,-3) for (x2,y2)
Slope of the line of (1,0) and (-1,-3) is:
m = 
= 
= 
(Simplify)
Slope of the line of (1,0) and (-1,-3) is
Answer: 0
First: Move constant to the left by adding its opposite to both sides
-3x+2y-7=7-7
Then: Change the signs on both sides of the equation
3x-2y+7
Equaling: 3x-2y+7=0
