Question

Write the definition of a function named averager that receives a double parameter and return-- as a double -- the average value that it has been passed so far. So, if you make these calls to averager, averager(5.0), averager(15.0), averager(4.3), the values returned will be (respectively): 5.0, 10.0, 8.1. Hint: use a static local variable to track the average of all the numbers been called.

Answer 1

Answer:

Following are the definition of function  

double averager (const double &x)  // function definition

{

static double z = 0.0;  // variable declaration

static size_t c = 0;

 c=c+1;  // increment of c by 1

z =z+ x;  // adding value  

return z /c ;   // return average  

}

Explanation:

Following are the description of statement  

• Create a function averager of double type that holds a parameter "x" of the double type .
• In this function we declared a variable "z" of a static double type that value is initialized by 0.
• The static variable is used to retain value.
• Declared a variable "c" of size_t type that holds a value 0 .
• After that increment the value of c by 1 .
• adding the value of "z" variable to the "x" and storing the result into the z variable.
• Finally return the average value