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zepelin [54]
3 years ago
6

What is the distance from the skydiving center?

Mathematics
1 answer:
Virty [35]3 years ago
4 0

Answer:

This is khan academy. I am pretty sure they have a video for this but whatever.

Step-by-step explanation:

So we are using sin, cosine, and tan. 3.4 is the hypotenuse. the side is X. The angle is 20 degrees. So, this is adjacent to hypotenuse. This means it is cosine.

3.4cos(20)= around 3.19

And thats that! let me know if this is wrong and I will try to fix it.

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There is a bag with only red marbles and blue marbles.The probability of randomly choosing a red marble is59.There are 63 marble
Elis [28]

Answer:

37

Step-by-step explanation:

59 percent times 63 in total marbles is 37

7 0
2 years ago
What is g(x)?
Vera_Pavlovna [14]

C

Step-by-step explanation:

This has a U like shape so it a parabola.

Parabola correlate with quadratic functions

y =  {ax}^{2}  + bx + c

Since it Going down, the answer is C -x^2.

3 0
2 years ago
Let X1 and X2 be two random variables following Binomial distribution Bin(n1,p) and Bin(n2,p), respectively. Assume that X1 and
ryzh [129]

Answer:

a) X1+X2 have distribution Bi(n1+n2, p)

b)

P(X1+X2 = 1 | X2 = 0) =  np(1-p)ⁿ¹⁻¹

P(X1+X2 = 1| X2 = 1) = (1-p)ⁿ¹

P(X1 + X2 = 1) = (1-p)ⁿ¹ * np(1-p)ⁿ²⁻¹+ (1-p)ⁿ²*np(1-p)ⁿ¹-¹

Step-by-step explanation:

Since both variables are independent but they have the same probability parameter, you can interpret that like if the experiment that models each try in both variables is the same. When you sum both random variables toguether, what you obtain as a result is the total amount of success in n1+n2 tries of the same experiment, thus X1+X2 have distribution Bi(n1+n2, p).

b)

Note that, if X2 = k, then X1+X2 = 1 is equivalent to X1 = 1-k. Since X1 and X2 are independent, then P(X1+X2 = 1| X2 = K) = P(X1=1-k|X2=k) = P(X1 = 1-k).

If k = 0, then this probability is equal to P(X1 = 1) = np(1-p)ⁿ¹⁻¹

If k = 1, then it is equal to P(X1 = 0) = (1-p)ⁿ¹

Thus,

P(X1+X2 = 1) = P(X1+X2 = 1| X2 = 1) * P(X2=1) + P(X1+X2 = 1| X2 = 0) * P(X2 = 0) = (1-p)ⁿ¹ * np(1-p)ⁿ²⁻¹+ (1-p)ⁿ²*np(1-p)ⁿ¹-¹

4 0
3 years ago
PLEASE HELP DUE SOON!WILL GIVE BRAINLIEST + POINTS!<br><br> Thank you and stay safe! :’)
Semmy [17]

Both those are drawn to scale.

5. Isosceles right triangle, sides in ratio 1:1:√2 = x:x:24 so x/24=1/√2,

x = 24/√2 = 24(√2/2) = 12√2

Answer: D. 12√2

6.  1:1:√2 = 10 : AB : BC

BC = 10√2

Answer: A. 10√2 ft

4 0
3 years ago
A tortoise and a hare are competing in a race around a 1600-meter track. The arrogant hare decides to let the tortoise have a 95
umka2103 [35]

Answer:

A. t=4n+950

B. h=9.5n

C. d=9.5n-(4n+950)

D. The tortoise will finish first.

Step-by-step explanation:

To find the first two equations, we put the rate at which they are traveling in front of the n, and then add where they start. Since the tortoise gets a 950 meter head start, we add 950. The hare is starting at the start line so we don't need to add anything.

For answer c, we need to subtract the two equations from each other to figure out when they would pass each other. d=(equation h)-(equation t).

For the final answer, all you need to do is plug the first two equations into a graph, and then find where each line is at the point of y 1,600. (To make the graphs I replaced the n with x and the t and h with y.) Using this, we are able to see who got there first, which was the tortoise.

6 0
3 years ago
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