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3 years ago

How to write: 3x-9=7y in standard form.

Mathematics

1 answer:

NikAS [45]3 years ago

5 0

Good evening from Canada!

Standard form: ax+by=c
3x-9=7y
3x-7y=9

Hope this helps!

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A gerbil cage,priced at $18, is discounted 20% for one week, and then this price is marked up 20%. is the price back to 20% expl

stiks02 [169]

No, it isn't!

first, the discount is 20 percent of 18 dollars, that is 18/5=3.6

this means that during the first week the prize is 18-3.6=14.4

now, the prize is marked up 20 % of 14.4! this is 2.88

so the prize later will be 14.4+2.88, that is 17.28, not 18

what is relevant here is what a number is a percent OF

6 0

3 years ago

The measure of one angle of an octagon is two times smaller that of the other seven angles. What is the measure of each angle?

Anestetic [448]

Answer:

7 of the angles measure 144 degrees each and one angle measures 72 degrees

Step-by-step explanation:

Let

x -----> represent the measures of the seven same-size angles,

x/2 ----> represent the measure of the one that is "two times smaller."

we know that

The sum of internal angles of a polygon can be calculated as:

$S=180^o(n-2)$

where

n is the number of sides of the polygon

In this case

n=8 (octagon)

substitute

$S=180^o(8-2)=1,080^o$

The linear equation that represent this problem is

$\frac{x}{2}+7x=1,080$

solve for x

$\frac{15x}{2}=1,080\\\\15x=2,160\\\\x=144^o$

$\frac{x}{2}=72^o$

therefore

7 of the angles measure 144 degrees each and one angle measures 72 degrees

7 0

3 years ago

The owner of a local nightclub has recently surveyed a random sample of n = 250 customers of the club. She would now like to det

seraphim [82]

Answer:

The required hypothesis to test is $H_0: \mu\leq 30$ and $H_1: \mu>30$ .

Step-by-step explanation:

Consider the provided information.

It is given that the nightclub has recently surveyed a random sample of n = 250 customers of the club.

She would now like to determine whether or not the mean age of her customers is over 30.

Null hypotheses is represents as $H_0$ . Thus the null hypotheses is shown as:

$H_0: \mu\leq 30$

The alternative hypotheses is represents as $H_1$ . Thus the alternative hypotheses is shown as:

$H_1: \mu>30$

Hence, the required hypothesis to test is $H_0: \mu\leq 30$ and $H_1: \mu>30$ .

8 0

3 years ago

10.) state whether the given side lengths can form a triangle

Verizon [17]

Answer:

A. 5,8,12, side lengths can form a triangle.

B. 20, 18, 2, side lengths can not form a triangle.

C. 15, 26 , 9, side lengths can not form a triangle.

D. 4.75, 12.25, 16.25, side lengths can form a triangle.

Step-by-step explanation:

We are given three sides in options A, B , C and D.

We need to check if the given sides would form a triangle or not.

Note: Sum of two sides is always greater than third sides in a triangle.

So, we need to check the sum of two sides of given sides length to check if sum is greater than third side length.

A. 5,8,12.

5+8 is greater than 12.

5+12 is greater than 8.

12+8 is greater than 5.

Therefore A. 5,8,12, side lengths can form a triangle.

B. 20, 18, 2

18+2 is not greater than 20.

Therefore B. 20, 18, 2, side lengths can not form a triangle.

C. 15, 26 , 9

15+9 is less than 26.

Therefore C. 15, 26 , 9, side lengths can not form a triangle.

D. 4.75, 12.25, 16.25.

4.75+12.25 is greater than 16.25.

4.75+16.25 is greater than 12.25.

12.25+16.25 is greater than 4.75.

Therefore D. 4.75, 12.25, 16.25, side lengths can form a triangle.

3 0

3 years ago

I’m not quite sure what the answers are, I have tired this problem a variety of times and still get it wrong.

leva [86]

Check the picture below, keeping in mind that opposides sides and interior angles in a parallelogram are congruent.

5 0

2 years ago