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kotegsom [21]
4 years ago
10

How can you do division in other ways like multiplication or something

Mathematics
2 answers:
attashe74 [19]4 years ago
6 0
Lets say our problem is 12÷24 which ofc equals 2, well we could figure it out by thinking hmmmm what is 12 x __ that equals 24?
kolbaska11 [484]4 years ago
6 0
You can do division with inverse operations for instance
36 divided by 9
9x( )=36 9x4=36
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Find the Area of the figure below, composed of a rectangle and a semicircle.
castortr0y [4]

Answer:

The answer is 20.

Step-by-step explanation:

10+12=22 round 22 to the nearest tenths and the answer is 20.

I hope is right.

7 0
2 years ago
Need help asap 15 points
otez555 [7]
1x10^-5         Answer  =2 x 10^9
2x10^-4       
8 0
3 years ago
Can someone help please
Mariulka [41]

Answer: k = 5

Step-by-step explanation:

Box A has more counters than box B

3 * 4 = 12

4 + 8 = 12

So if k was equal to 4, then both boxes would have the same amount.

3 * 5 = 15

5 + 8 = 13

15 > 13

If k was equal to 5, then Box A would contain more counters than Box B.

4 0
3 years ago
1. Solve each equation. For each step. identify the property used.
ehidna [41]

Answer:

I will put the answer below, but here is a tip:

Use PEMDAS. PEMDAS IS THIS:

P ( ) parenthesis

E y+x exponents

M x multiplication

D ÷ division

A + addition

S - subtraction

Key:

Property used=PU

Step-by-step explanation:

Part A:

18= 6x(2x-3)  PU=( ), y+x, x, & -

Part B:

8+3b-1 PU= y+x, +, & -

Part C:

=12 PU= =

Part D:

14+3n=8n-3x(1-4) PU= ( ), y+x, x, +, & -

Part E:

22x+11-4x-7 PU= y+x, +, & -

           

6 0
3 years ago
3a-2/3+2a+3/2=a+7/6.find a ​
S_A_V [24]

I think your question seems to be ;

{\:\implies \quad \sf 3a-\dfrac23 +2a+\dfrac32 =a+\dfrac76}

So I will be solving for that ;

{\:\implies \quad \sf 3a+2a+\left(\dfrac32 -\dfrac23\right)=a+\dfrac76}

{\:\implies \quad \sf 5a+\left(\dfrac{9-4}{6}\right)=a+\dfrac76}

{\:\implies \quad \sf 5a+\dfrac56 =a+\dfrac76}

{\:\implies \quad \sf 5a-a=\dfrac76 -\dfrac56}

{\:\implies \quad \sf 4a=\dfrac{7-5}{6}}

{\:\implies \quad \sf 4a=\dfrac26}

{\:\implies \quad \sf 4a=\dfrac13}

{\:\implies \quad \sf a=\dfrac{1}{3\cdot 4}}

{\:\implies \quad \bf \therefore \quad \underline{\underline{a=\dfrac{1}{12}}}}

7 0
3 years ago
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