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nika2105 [10]
3 years ago
10

Find the answer to (6!) in math

Mathematics
2 answers:
RoseWind [281]3 years ago
6 0
1*2*3*4*5*6=720.
Hope I helped
Alex Ar [27]3 years ago
3 0
\boxed{n!=1\cdot2\cdot3\cdot4\cdot...\cdot n}\\\\6!=1\cdot2\cdot3\cdot4\cdot5\cdot6=\boxed{720}
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a .8

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d 125.0

Step-by-step explanation:

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Jane is studying the weather in Alaska. she recorded the temperature for four days in January, in degrees Fahrenheit, as shown i
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The following equation is a linear equation that has a slope of 3 and a y-intercept of positive 2:
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The thumb length of fully grown females of a certain type of frog is normally distributed with a mean of 8.59 mm and a standard
PilotLPTM [1.2K]

Answer:

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 8.59, \sigma = 0.63

Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

This is 1 subtracted by the pvalue of Z when X = 9.08. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.08 - 8.59}{0.63}

Z = 0.78

Z = 0.78 has a pvalue of 0.7823

1 - 0.7823 = 0.2177

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

8 0
3 years ago
Can anyone plz help me with this problem im a little stuck on it...
Greeley [361]

Answer:

18

Step-by-step explanation:

3×6 = 18

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below ÷)

6 0
4 years ago
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