22.5 miles long
basically all you have to do is count out the factors until you reach two number of 45 apart
DIFFERENCE
7MPH 5MPH BETWEEN THEM
7 5 2
14 10 4
21 15 6
28 20 8
35 25 10
42 30 12
49 35 14
56 40 16
63 45 18
70 50 20
77 55 22
84 60 24
91 65 26
98 70 28
105 75 30
112 80 32
119 85 34
126 90 36
133 95 38
140 100 40
147 105 42
154 110 44
161 115 46
considering the differences are even it means it has to fall in the middle. if you count from the top it is 22.5 numbers down giving you the number of miles.
I'm sure there is an easier way but this is how i would solve it. :)
Answer:
*followed*
Step-by-step explanation:
Answer:
The ratio of used stamps and total stamps can be represented by three fifths.
Step-by-step explanation:
It is give that Jamal has 4 new stamps and 6 used stamps.
New stamps = 4
Used stamps = 6
Total stamps = New stamps + Used stamps = 4 + 6 = 10
We need to find the ratio that can be represented by three fifths
Therefore, the ratio of used stamps and total stamps can be represented by three fifths.
If the length, breadth and height of the box is denoted by a, b and h respectively, then V=a×b×h =32, and so h=32/ab. Now we have to maximize the surface area (lateral and the bottom) A = (2ah+2bh)+ab =2h(a+b)+ab = [64(a+b)/ab]+ab =64[(1/b)+(1/a)]+ab.
We treat A as a function of the variables and b and equating its partial derivatives with respect to a and b to 0. This gives {-64/(a^2)}+b=0, which means b=64/a^2. Since A(a,b) is symmetric in a and b, partial differentiation with respect to b gives a=64/b^2, ==>a=64[(a^2)/64}^2 =(a^4)/64. From this we get a=0 or a^3=64, which has the only real solution a=4. From the above relations or by symmetry, we get b=0 or b=4. For a=0 or b=0, the value of V is 0 and so are inadmissible. For a=4=b, we get h=32/ab =32/16 = 2.
Therefore the box has length and breadth as 4 ft each and a height of 2 ft.
