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avanturin [10]
3 years ago
10

Combine like terms to create an equivalent expression.

Mathematics
2 answers:
poizon [28]3 years ago
5 0

Answer is in the file below

tinyurl.com/wpazsebu

Lesechka [4]3 years ago
5 0

Your Welcome!!!!

The answer is in the picture!!!! :3

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Applications: Sarah's Pet Store never has more than a combined total of 16 cats and dogs. She also never has more than 9 cats. W
ankoles [38]

The possible solution is 12 cats and 4 dogs in Sarah's store.

Let x represent the number of cats and y represent the number of dogs.

Since Sarah's Pet Store never has more than a combined total of 16 cats and dogs. Hence:

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Also, She also never has more than 9 cats. Therefore:

  • x > 9

The solution to the inequality is graphed. From the graph, the possible solution is 12 cats and 4 dogs

Find out more on inequalities at: brainly.com/question/24372553

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2 years ago
Which of the following expressions, if any, are equal for all real numbers "m"? I. square root of m^2 II. |-m| III. - |m| 
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SEE IMAGE! Which of the following expressions is equal to the value of x?
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A) 0.9(sin50)

Step-by-step explanation:

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sin 50 = x /.9

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3 years ago
Pleases someone explain
Nikolay [14]

When you have a negative exponent, you move the base with the negative exponent to the other side of the fraction to make the exponent positive.

For example:

\frac{1}{y^{-2}} =\frac{y^2}{1} or y^2

2x^{-3} or \frac{2^1x^{-3}}{1} =\frac{2}{x^3}

\frac{1}{x^{-5}} =x^5

When a base with an exponent is divided by a base with an exponent, you subtract the exponents together. (But you can only combine the exponents when the bases are the same)

For example:

\frac{x^2}{y}   (can't combine because they have different bases of y and x)

\frac{x^5}{x^3} =x^{(5-3)}=x^2

\frac{2^2}{2} =2^{(2-1)}=2^1 = 2

When you multiply an exponent directly to a base with an exponent, you multiply the exponents together.

For example:

(x^2)^3=x^{(2*3)}=x^6

(y^2)^{10}=y^{(2*10)}=y^{20}

\frac{2e^0}{(e^{-3})^2}     First multiply the exponents together in the denominator

\frac{2e^0}{e^{(-3*2)}}= \frac{2e^0}{e^{-6}}        Now subtract the exponents together

2e^{(0-(-6))}  (two negative signs cancel each other out and become positive)

2e^{(0+6)}

2e^6

7 0
3 years ago
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