A set of equations is given below:

1 answer:

7 0

Y = 3x + 7....slope is 3, y int is 7
y = 3x + 2...slope is 3, y int is 2

when the slopes are the same, but the y intercepts different, then it is a parallel line with no solutions.

little tip :
slopes same, y int different, = no solution
slopes same, y int same = infinite solutions
slopes different, y int different = 1 solution

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The local furniture store pays $120 for a lamp and sells it with a 20% markdown. What is the

Fantom [35]

Answer:$24

Step-by-step explanation:

To find 20 percent of a number you multiply the number by 20, then multiply the answer by .01.

120 x 20 = 2400

2400 x .01 = 24

8 0

3 years ago

Read 2 more answers

I will give brainliest to best answer

lorasvet [3.4K]

That's a Congruent Triangle question.

The first thing that we should to analize is it: What figure is EFGH? The question say for us that $\overline{EF} \cong \overline{GH}$ and $\overline{EH} \cong \overline{GF}$ , therefore, EFGH is a parallelogram because its parallel sides are congruents (equals).

Now, we should to proof that $\triangle EFH \cong \triangle GHF$ . The simbol "≅" means congruence, that is, $\triangle EFH \cong \triangle GHF$ means that the triangles EFH and GHF are equals.

Let's proof:

$\overline{HF}$ is a diagonal of the parallelogram EFGH. When we have a diagonal in a parallelogram, the opposite angles are congruents (look at the picture: the blue angles are congruent and the red angles are congruents too). Therefore, $E\hat{F}H \cong F\hat{H}G$ and $E\hat{H}F \cong H\hat{F}G$ .

Both triangle has a comum side: the diagonal $\overline{HF}$ . The diagonal $\overline{HF}$ is between two angles that we know that are congruents, Therefore, by the case ASA (Angle, Side, Angle), we proof that $\triangle EFH \cong \triangle GHF$ .