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3 years ago

Can someone help me out - Please show your work

Mathematics

2 answers:

butalik [34]3 years ago

8 0

Hey there!

If you look at the image you've been given, you can see that there are four complete repeats of each individual angle. What I mean by this is that you can take that angle, lay it on top of three other angles you've been shown, and it will be the exact same. These are corresponding angles.

An example would be (1, 9, 3, and 11). Any of these are the exact same angle, placement and degree included, as the others. The other examples in this problem would be (2, 10, 4, and 12), (6, 14, 8, and 16), and (5, 13, 7, and 15).

Your answer will be C, angle 3 and angle 11.

Hope this helped you out! :-)

valentinak56 [21]3 years ago

3 0

The answer is C hope this helps

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Pavlova-9 [17]

Answer: 6*2*2=24 cubic feet

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3 years ago

Suppose you toss a fair coin 10 times, let X denote the number of heads. (a) What is the probability that X=5? (b) What is the p

zubka84 [21]

Answer: The required answers are

(a) 0.25, (b) 0.62, (c) 6.

Step-by-step explanation: Given that we toss a fair coin 10 times and X denote the number of heads.

We are to find

(a) the probability that X=5

(b) the probability that X greater or equal than 5

(c) the minimum value of a such that P(X ≤ a) > 0.8.

We know that the probability of getting r heads out of n tosses in a toss of coin is given by the formula of binomial distribution as follows :

$P(X=r)=^nC_r\left(\dfrac{1}{2}\right)^r\left(\dfrac{1}{2}\right)^{n-r}.$

(a) The probability of getting 5 heads is given by

$P(X=5)\\\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}\\\\\\=\dfrac{10!}{5!(10-5)!}\dfrac{1}{2^{10}}\\\\\\=0.24609\\\\\sim0.25.$

(b) The probability of getting 5 or more than 5 heads is

$P(X\geq 5)\\\\=P(X=5)+P(X=6)+P(X=7)+P(X=8)+P(X=9)+P(X=10)\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}+^{10}C_6\left(\dfrac{1}{2}\right)^6\left(\dfrac{1}{2}\right)^{10-6}+^{10}C_7\left(\dfrac{1}{2}\right)^7\left(\dfrac{1}{2}\right)^{10-7}+^{10}C_8\left(\dfrac{1}{2}\right)^8\left(\dfrac{1}{2}\right)^{10-8}+^{10}C_9\left(\dfrac{1}{2}\right)^9\left(\dfrac{1}{2}\right)^{10-9}+^{10}C_{10}\left(\dfrac{1}{2}\right)^{10}\left(\dfrac{1}{2}\right)^{10-10}\\\\\\=0.24609+0.20507+0.11718+0.04394+0.0097+0.00097\\\\=0.62295\\\\\sim 0.62.$

(c) Proceeding as in parts (a) and (b), we see that

if a = 10, then

$P(X\leq 0)=0.00097,\\\\P(X\leq 1)=0.01067,\\\\P(X\leq 2)=0.05461,\\\\P(X\leq 3)=0.17179,\\\\P(X\leq 4)=0.37686,\\\\P(X\leq 5)=0.62295,\\\\P(X\leq 6)=0.82802.$

Therefore, the minimum value of a is 6.

Hence, all the questions are answered.

3 0

4 years ago

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3 years ago

A line goes through the points (1,8) and (9,12) what is the slope of the line? <br>Plz explain

Igoryamba

Answer:

2/3 or 0.67

Step-by-step explanation:

Slope = y2 - y1 /x2 - x1

Given

x1 = 1

y1 = 8

x2 = 9

y2 = 12

Slope = 12 - 8 /9 - 1

= 4/6

Reduce is by 2

2/3

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3 years ago

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svetlana [45]

Answer:

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