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Eva8 [605]
3 years ago
6

Need Help*Please Show Work*​

Mathematics
1 answer:
sergejj [24]3 years ago
8 0

Hi there! :)

Answer:

y = -2x + 3

Step-by-step explanation:

We can write an equation in slope-intercept form. Use the slope formula to find the rate of change in the table:

m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}

Plug in values from the table:

m  = \frac{5 - 7}{-1 - (-2)}

Simplify:

m = -2 (rate of change)

Use a point from the table (-2, 7) and the slope to solve for the equation for the linear function:

7 = -2(-2) + b

7 = 4 + b

7 -4 = b

b = 3

Rewrite:

y = -2x + 3 is the equation for the linear function.

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Can someone help me please
svp [43]

Answer:

4

Step-by-step explanation:

if the area is 1/4 that would mean that the sides are equal to 1/2. if you stretch 1/2 out 4 times longer that would be equal to 2. 2 x 2 = 4

6 0
2 years ago
Please give me the right answer
ivann1987 [24]

Answer:j

Step-by-step explanation:

If it’s closed it would be greater than -2 but since it’s open it’s equal or greater than

8 0
3 years ago
Simplify the expression. (16y54y3)12 Enter your answer in the box.
sp2606 [1]

Answer:

Simplify the expression: (16y^{\frac{5}{4}}y^3)^{\frac{1}{2}}

Use the exponent power:

  • a^n \cdot a^m = a^{n+m}
  • \sqrt[n]{a^n} =a
  • (a^n)^m = a^{nm}

(16y^{\frac{5}{4}}y^3)^{\frac{1}{2}}

Apply the given rules;

(16y^{\frac{5}{4} +3} )^{\frac{1}{2}}

Simplify:

(16y^{\frac{17}{4}} )^{\frac{1}{2}}

then;

(16)^{\frac{1}{2}} \cdot (y^{\frac{17}{4}})^{\frac{1}{2}} = 4y^{\frac{17}{8}}

Therefore, the simplified expression of (16y^{\frac{5}{4}}y^3)^{\frac{1}{2}} is, 4y^{\frac{17}{8}}


7 0
2 years ago
What is fifty four divides by four?
galben [10]
54 divided by four is 13.5 or 27/2
4 0
3 years ago
Read 2 more answers
What are the solution of x^2-2x+17=0
ddd [48]

Answer:

<h2>x = 1 - 4i or x = 1 + 4i</h2>

Step-by-step explanation:

x^2-2x+17=0\qquad\text{subtract 17 from both sides}\\\\x^2-2x=-17\\\\x^2-2(x)(1)=-17\qquad\text{add}\ 1^2\ \text{to both sides}\\\\x^2-2(x)(1)+1^2=-17+1^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\(x-1)^2=-17+1\\\\(x-1)^2=-16

x-1=-4i\ \vee\ x-1=4i\qquad\text{add 1 to both sides}\\\\x=1-4i\ \vee\ x=1+4i

4 0
2 years ago
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