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sertanlavr [38]
3 years ago
10

Which equation could be solved using this application of the quadratic formula? x = (- 3 plus/minus sqrt(3 ^ 2 - 4(1) * (24)))/(

2(1)) A. x ^ 2 + 6x + 24 = 3x B 3x ^ 2 + 3x + 24 = 3 C. x ^ 2 + 3x - 24 = 3 D x ^ 2 + 3x + 24 = 3
Mathematics
1 answer:
Zina [86]3 years ago
7 0

Answer:

x^2 + 3x + 24 = 0

Step-by-step explanation:

Given

x = \frac{-3\±\sqrt{3^2 - 4*1*24}}{2*1}

Required

Select equation with the above solution

The solution is represented as:

x = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}

By comparison:

b= 3       a = 1       c = 24

So, the equation is:

ax^2 + bx + c = 0

x^2 + 3x + 24 = 0

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