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xz_007 [3.2K]
3 years ago
5

Point C'(-4,-3) is the image of C(-2, -3) under a translation.

Mathematics
1 answer:
Degger [83]3 years ago
5 0

C(-2,-3) moves to C ' (-4, -3)

The x coordinate changes from -2 to -4. So we subtracted -2 from the x coordinate. Algebraically, x becomes x-2

The y coordinates are both -3, so nothing changes here.

The translation rule is (x,y) \to (x-2, y)

This represents a shift of 2 units to the left.

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The question is in the picture
Blizzard [7]
I think is that one that say <-5,-3> yeah because 3×5=15 you have to choose what other number × 3 that equal to that following answer.
3 0
2 years ago
Shade the model to show the decimal 0.542 using 100 grid and 10 grid
kherson [118]

0.542=0.500 + 0.040+0.002

          = \frac{5}{10} + \frac{4}{100} +\frac{2}{1000}

         =5 tenth + 4 hundredths + two thousandths

One tenth = \frac{1}{10}

One Hundredth= \frac{1}{100}

One thousandth= \frac{1}{1000}


8 0
3 years ago
Read 2 more answers
Math question:
nignag [31]

Answer: 352

Step-by-step explanation:

3 0
2 years ago
How to solve Y=1/2X+2
Oxana [17]
<span>x-intercept is when y = 0

0 = -1/2x - 2
1/2x = -2
x = -4
x-intercept = (-4,0)

y-intercept is when x = 0

y = -1/2(0) - 2
y = -2
y-intercept = (0, -2)
(note that in the form y = mx+b, b is the y-intercept, so in y = -1/2x - 2, -2 is the y-intercept)

Now to graph, simply plot these two points (-4, 0) and (0, -2) and draw a line between them.

Best of luck!</span>
8 0
3 years ago
Which equation is parallel to the line LaTeX: y=\frac{1}{2}x+3y = 1 2 x + 3and passes through the point (10, -5)?
sukhopar [10]

Answer:

Equation\ of\ line:\ y=\frac{1}{2}x-10

Step-by-step explanation:

Let\ the\ required\ equation\ is\ y=mx+c\\\\where\ m\ is\ the\ slope\ of\ the\ equation\ and\ c\ is\ y-intercept\\\\It\ is\ parallel\ to\ the\ equation\ y=\frac{1}{2}x+3\\\\Hence\ slope\ of\ these\ two\ lines\ will\ be\ same.\\\\Slope\ of\ y=\frac{1}{2}x+3\ is\ \frac{1}{2}\\\\Hence\ slope\ of\ y=mx+c\ is\ \frac{1}{2}\Rightarrow m=\frac{1}{2}\\\\Equation:y=\frac{1}{2}x+c\\\\Line\ passes\ through\ (10,-5).\ Hence\ this\ point\ satisfies\ the\ equation\ of\ line.\\\\-5=\frac{1}{2}\times 10+c

-5=-5+c\\\\c=-10

Equation\ of\ line:\ y=\frac{1}{2}x-10

8 0
2 years ago
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