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Alenkinab [10]
3 years ago
12

Ted likes to run long distances. He can run 20 km in 95 minutes.He wants to know how many kilometers he will go if he runs the s

ame pace for 285 minutes. How far will Ted run in 285 minutes
Mathematics
2 answers:
gladu [14]3 years ago
5 0
You just have to cross multiply. 20 x 285 = 5700. 5700 / 95 = 60.

He will run 60km
gavmur [86]3 years ago
3 0
Ted runs in 95 minutes= 20 km
Ted runs in 1 minute= 20/95
Ted runs in 285 minutes= 20/95*285= 60km
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I need some help with this calculus 1 question.
Cerrena [4.2K]

Answer:

(a) f'(1)=-4

(b) y+4x-4=0

Step-by-step explanation:

<u>Tangent Line of a Function</u>

Given f(x) a real differentiable function in x=a, the slope of the tangent line of the function in x=a is given by f'(x=a). Where f' is the first derivative of f.

We are given

y=x-x^5

The derivative is

y'=1-5x^4

(a) The slope of the tangent line at (1,0) is

f'(1)=1-5\cdot 1^4=-4

f'(1)=-4

(b) The equation of the tangent line can be found with the general formula of the line:

y-y_o=m(x-x_o)

Where m is the slope and the point (xo,yo) belongs to the line. We have m=-4, xo=1, yo=0, thus

y-0=-4(x-1)

Or, equivalently

y+4x-4=0

3 0
2 years ago
When i am solving for the sides of a right triangle when will i use trigonometric functions
AnnZ [28]

Answer:

The ratios of the sides of a right triangle are called trigonometric ratios. We need to use trigonometric functions to find them when we don't have any angle other than 90 degree shown.

Three common trigonometric ratios are the sine (sin), cosine (cos), and tangent (tan). These are defined for acute angle.

However when we have one angle given with the 90 degree we can deduct without trigonometry but we would use all angles to find the hypotenuse or all angles to find the side of a right angle.

Alternatively, we cna do this with one given angle but if we have one, we might as well work out the other one without trigonometry and do a division with Sin = 25 (sin 35) sin 90  / sin 55

is one example when given the base 25ft that would find the hypotenuse or the length of elevation for buildings looking down or zip-wire questions.

Step-by-step explanation:

       A

       |  \

       l     \

4cm|        \ 5cm

       |          \

       |            \

   B | -  -  -  -  \ C      

          3cm

Suppose we wanted to find sin( A) in△ABC    

(The height of the wall in elevation questions would be used above the base shown 3cm at the start) Sin = 3 (sin 35)° sin 90°  / sin 55° to find the height side (4).

Sine is defined as the ratio of the opposite to the hypotenuse

sin(A) =  hypotenuse          ​= AB/BC        = 3/5

             / opposite

                                           

​

​

6 0
3 years ago
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