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Ipatiy [6.2K]
3 years ago
6

consider the four corners of the front wall of a rectangular class room (upper right, upper left, lower left, upper left) which

of these points are coplanar with the plane of the front wall.
Mathematics
1 answer:
professor190 [17]3 years ago
3 0
(You copied 'upper left' twice, and you left out 'lower right'. 
But we know what you mean.)

If those are the corners of the wall, then they're ALL in the plane of
the wall (coplanar with it).
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Pls help!Please help
mamaluj [8]

Answer:

4,6,8,10

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Step-by-step explanation:

Part A :

4,6,8,10

$10,$15,$20,$25

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5 0
3 years ago
Find the center of a circle with the equation: x2 y2−32x−60y 1122=0 x 2 y 2 − 32 x − 60 y 1122 = 0
mixas84 [53]

The equation of a circle exists:

$(x-h)^2 + (y-k)^2 = r^2, where (h, k) be the center.

The center of the circle exists at (16, 30).

<h3>What is the equation of a circle?</h3>

Let, the equation of a circle exists:

$(x-h)^2 + (y-k)^2 = r^2, where (h, k) be the center.

We rewrite the equation and set them equal :

$(x-h)^2 + (y-k)^2 - r^2 = x^2+y^2- 32x - 60y +1122=0

$x^2 - 2hx + h^2 + y^2 - 2ky + k^2 - r^2 = x^2 + y^2 - 32x - 60y +1122 = 0

We solve for each coefficient meaning if the term on the LHS contains an x then its coefficient exists exactly as the one on the RHS containing the x or y.

-2hx = -32x

h = -32/-2

⇒ h = 16.

-2ky = -60y

k = -60/-2

⇒ k = 30.

The center of the circle exists at (16, 30).

To learn more about center of the circle refer to:

brainly.com/question/10633821

#SPJ4

7 0
2 years ago
What is the value of m in this equation -4(m+6)=-8
Darina [25.2K]
-4m-24=-8
(add 24 to both sides)
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(divide by -4 on both sides)
m=-4
8 0
3 years ago
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Answer:

1/4

Step-by-step explanation:

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3 years ago
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I need help with #11 MULTIPLE CHOICE
wel

Answer:

d

Step-by-step explanation:

8 0
3 years ago
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