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siniylev [52]
3 years ago
14

Can someone please explain this question to me and how do you do it???

Mathematics
1 answer:
svetlana [45]3 years ago
5 0

Step-by-step explanation:

is it your homework or what

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6.9•10 to the fourth power divided by 6.6•10 to the negative 5
e-lub [12.9K]
23/200
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3 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!
svet-max [94.6K]

Answer:

tan (C) = 2.05

Step-by-step explanation:

Given:

A right angled triangle CDE right angled at ∠D.

Side CD = 39

Side DE = 80

Side CE = 89

We know, from trigonometric ratios that, the tangent of any angle is equal to the ratio of the opposite side to the angle and the adjacent side of the angle.

Therefore, tangent of angle C is given as:

\tan(\angle C)=\frac{DE}{CD}

Plug in the given values and solve for angle C.This gives,

\tan(\angle C)=\frac{80}{39}\\\\\tan(\angle C)=2.051\approx 2.05(Rounded\ to\ nearest\ hundredth)

Therefore, the measure of tangent of angle C is 2.05.

4 0
3 years ago
QUESTION 5 · 1 POINT
natali 33 [55]

Answer:

( x - 1) ( 2x + 3)

Step-by-step explanation:

It's actually the other way round.

2x^2- + x - 3

( 2x^2 - 2x) + (3x-3)

2x ( x-1 ) + 3( x-1)

( x -  1)(2x+3)

Its the other way around

HOPE IT HELPED

3 0
3 years ago
What is the value of 5^3¡^9
OLEGan [10]

Answer:

125i

Step-by-step explanation:

We want to find

5^3i^9

This can be rewritten as;

5^3i^8\times i

5^3(i^2)^4\times i

Recall that; i^2=-1

5^3(-1)^4\times i

We evaluate now to obtain;

125(1)\times i=125i

6 0
3 years ago
Matrix multiplication was used to encode a message using the given encoding matrix: [i 47 A=1 |-1 -3] The original message was c
nadya68 [22]

Answer:

A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right] message SHOW_ME_THE_MONEY_  

Step-by-step explanation:

The matrix

A=\left[\begin{array}{cc}1&4\\-1&-3\end{array}\right]\rightarrow |A|=(1 \times -3)-(-1\times 4)=1\\\rightarrow A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right] \\

We can check that in fact A*A^⁻1=I_2 the identity matrix of size 2 x 2.

Now the message was divided in 1 x 2 matrices, then we have that the sequence given is the result of multiplying m by A, so to get m again we multiply now by A^⁻1. and we get the next table

Encoded message    Decoded message    message in letters by association

11 52        19 8    S H

-8 -9         15 23  O W

-13 -39        0 13   _ M

5 20         5 0   E _

12 56        20 8    T H

5 20         5 0    E _

-2 7           13 15  M O

9 41         14 5   N E

25 100       25 0    Y _

Then the message decoded is SHOW_ME_THE_MONEY_                                

3 0
3 years ago
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