Answer:
![W_{max}=480m\\ L_{max}=160m](https://tex.z-dn.net/?f=W_%7Bmax%7D%3D480m%5C%5C%20L_%7Bmax%7D%3D160m)
Step-by-step explanation:
Since we know we only have 640 feet of fence available, we know that L + W + L = 640,
2L + W = 640. This allows us to represent the width, W, in terms of L: W = 640 – 2L
Remember, the area of a rectangle is equal to the product of its width and length, therefore,
Notice that, quadratic has been vertically reflected, since the coefficient on the squared term is negative, so the graph will open downwards, and the vertex will be a maximum value for the area.
recall,
Since our function is A(L)=640L-2L², we get
plug in the value of a and b into the first formula:
![L_{max}=-(640)/2(-2)\implies 160](https://tex.z-dn.net/?f=L_%7Bmax%7D%3D-%28640%29%2F2%28-2%29%5Cimplies%20160%20)
![A(L)_{max}=640(160)-2(160)^2\implies 76800](https://tex.z-dn.net/?f=A%28L%29_%7Bmax%7D%3D640%28160%29-2%28160%29%5E2%5Cimplies%2076800%20)
hence,the dimensions of the pen that will maximize the area are<u> </u><u>L=</u><u>1</u><u>6</u><u>0</u><u>m</u><u> </u>and<u> </u><u>W=</u><u>7</u><u>6</u><u>8</u><u>0</u><u>0</u><u>/</u><u>1</u><u>6</u><u>0</u><u>=</u><u>4</u><u>8</u><u>0</u><u>m</u>
and we're done!
Answer:
2.052
Step-by-step explanation:
I hope it helped lot sj
Answer:
See below.
Step-by-step explanation:
He does not have enough to loose 2,000,000 at that point, so this whole problem is nonsense.
Answer: Yes, ![\bold{f^{-1}(x)=\dfrac{x+6}{3}}](https://tex.z-dn.net/?f=%5Cbold%7Bf%5E%7B-1%7D%28x%29%3D%5Cdfrac%7Bx%2B6%7D%7B3%7D%7D)
<u>Step-by-step explanation:</u>
f(x) = 3x - 6 is a line so it is a function because
it passes the vertical line test
and the horizontal line test
To find the inverse, swap the x's and y's and solve for y
![y=3x-6\\\\\\\text{Swap the x's and y's:}\qquad x=3y-6\\\\\text{Add 6 to both sides:}\qquad x+6=3y\\\\\text{Divide both sides by 3:}\qquad \dfrac{x+6}{3}=y](https://tex.z-dn.net/?f=y%3D3x-6%5C%5C%5C%5C%5C%5C%5Ctext%7BSwap%20the%20x%27s%20and%20y%27s%3A%7D%5Cqquad%20x%3D3y-6%5C%5C%5C%5C%5Ctext%7BAdd%206%20to%20both%20sides%3A%7D%5Cqquad%20x%2B6%3D3y%5C%5C%5C%5C%5Ctext%7BDivide%20both%20sides%20by%203%3A%7D%5Cqquad%20%5Cdfrac%7Bx%2B6%7D%7B3%7D%3Dy)