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lora16 [44]
2 years ago
6

^^^Can someone help ^^^

Mathematics
1 answer:
alex41 [277]2 years ago
3 0
Answer is 1.6

Because you can see the shape with the side of 5 is bigger than the shape with the side with the 3, so you divide the bigger by the smaller
5 / 3 = 1.6
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Jaelynn has 30 times as many stickers as her brother. Her brother has 8 stickers. How many stickers does Jaelynn have?
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6 0
3 years ago
Read 2 more answers
Please Help! Will Mark Brainliest
Gennadij [26K]

Answer:

x = 4

Step-by-step explanation:

Using the sine ratio on right triangle KJL

and the exact value sin30° = \frac{1}{2}

sin30° = \frac{opposite}{hypotenuse} = \frac{JL}{KL} = \frac{JL}{8\sqrt{2} } = \frac{1}{2} ( cross- multiply )

2JL = 8\sqrt{2} ( divide both sides by 2 )

JL = 4\sqrt{2}

---------------------------------------------------------

Using the sine ratio in right triangle JLM

and the exact value sin45° = \frac{1}{\sqrt{2} }

sin45° = \frac{opposite}{hypotenude} = \frac{LM}{JL} = \frac{x}{4\sqrt{2} } = \frac{1}{\sqrt{2} } ( cross- multiply )

x × \sqrt{2} = 4\sqrt{2} ( divide both sides by \sqrt{2}

x = 4

8 0
3 years ago
How to solve this linear equation step by step please
mote1985 [20]
\bf \cfrac{3}{c^2-4c}-\cfrac{9}{2c^2+3c}=\cfrac{2}{2c^2-5c-12}\\\\\\ 
\begin{cases}
c^2-4c=&c(c-4)\\
2c^2+3c=&c(2c+3)\\\\
2c^2-5c-12=
&(2c+3)(c-4)
\end{cases}\\\\
-------------------------------\\\\
\textit{therefore, our LCD for the \underline{left-side} will have to be }\underline{c(c-4)(2c+3)}\\\\
-------------------------------\\\\

\bf \cfrac{3}{c(c-4)}-\cfrac{9}{c(2c+3)}=\cfrac{2}{(2c+3)(c-4)}
\\\\\\
\cfrac{3(2c+3)-9(c-4)}{c(c-4)(2c+3)}=\cfrac{2}{(2c+3)(c-4)}
\\\\\\
\cfrac{6c+9-(9c-36)}{c(c-4)(2c+3)}=\cfrac{2}{(2c+3)(c-4)}
\\\\\\
\cfrac{6c+9-9c+36}{1}=\cfrac{2[c(c-4)(2c+3)]}{(2c+3)(c-4)}
\\\\\\
-3c+45=2c\implies 45=5c\implies \cfrac{45}{5}=c\implies 9=c
7 0
2 years ago
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spayn [35]

Answer:

surface area

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6 0
2 years ago
Una escalera de 65 decímetros de apoyo en una pared vertical de modo que el pie de la escalera está a 25 decímetros de la pared
user100 [1]

Answer:

Can you English translate this question please so i can help you?

Step-by-step explanation:

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