Answer:
A minimum of 10 dimes and 11 quarters is what Alexandra will have
Step-by-step explanation:
Let
d = number of dimes
q = number of quarters
Since she has 21 coins altogether,
d + q = 21------------------------equation 1
- If these coins are worth $3.75 then
0.10 x d + 0.25 x q = 3.75
- which is 0.10d +.25q =3.75
--------------------------equation 2
where $.10 is the value of one dime and $.25 is the value of one quarter
make d the subject of formula from equation 1 d = 21 -q----------equation 3
insert it in equation 2
0.10d +0.25q =3.75
0.10(21-q) + 0.25q = 3.75
0.1(21)-0.1q+0.25q=3.75
2.1 +0.15q = 3.75
0.15q = 3.75-2.1 = 1.65
q = 1.65/0.15 =165/15 =11
- since we have the value of q insert in equation 3
d = 21 - q
d = 21-11
d = 10
Alexandra has 10 dimes and 11 quarters.
from my calculation i can see that the a minimum of 10 dimes and 11 quarters is what Alexandra will have
To estimate the distance between the tip of his fishingrod which is above the water and the hook which is below the water, you will need to estimate the absolute values of both distances.
|53 3/4| + |12 2/3|54 + 1367 ft
Trents estimate is not reasonable because you would around both of these values up to the next whole number making it greater than 65.
You distribute the three into the numbers in parentheses. -3+24n+6n. Then combine like terms. -3+30n
But I may be wrong.
Divide the number of ice-cream bars into the number of people. Example: say you have 20 ice cream bars and 10 people you divide 20/10 and get 2 ice cream bars per person. Hope this helped.
Ok, so the discount is given in a percentage, in this case 10%. The sale price is going to reflect 10% of the original price minus the discount, so...
Sale $ = original$ - original $ x .10
If we use some algebra, we can reorganize the equation to solve for the original price...
Sale $ = original$ - original $ x .10
Sale $ = original$ (1 - .10)
Sale $ = original$ x .90
original$ = sale$/.90
So now we can plug in our values
original price = 50/.90
original price = 55.55555 = $55.55 to the nearest nickel
