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Llana [10]
3 years ago
13

Simple random sampling uses a sample of size n from a population of size N to obtain data that can be used to make inferences ab

out the characteristics of a population. Suppose that, from a population of 52 bank accounts, we want to take a random sample of four accounts in order to learn about the population. How many different random samples of four accounts are possible

Mathematics
1 answer:
Rama09 [41]3 years ago
3 0

Answer:

Answer is 270725

Step-by-step explanation:

Answer is in the following attachments

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Explain how to do this problem in steps and include answers as well
vlabodo [156]
8(4x - 5)-12=20x-10

32x - 40-12=20x-10

32x -52=20x-10

32x -52 -20x=-10

12x -52=-10

12x =-10 +52

12x =42

x= \frac{42}{12}

x =  \frac{7}{2}

x=3 \frac{1}{2}  ≈ 3.5
5 0
4 years ago
Read 2 more answers
In a fruit survey, children choose their favorite fruit out of apples, bananas and watermelon. 29% chose apples, 41% chose banan
Alex73 [517]

Answer: 30% chose watermelons.

Step-by-step explanation:

if 29% chose apples and 41% chose bananas, that equals 70%

So, out of 100%, 70% chose both apples and bananas, which leaves 30% for watermelons.

8 0
3 years ago
1. In the formula V = lwh, the variable h needs
ANTONII [103]

Answer:

H=\frac{V}{LW}

see the explanation

Step-by-step explanation:

we know that

Using inverse operations, the  formula can be rearranged to solve for any one of the variables that might be  unknown.

we have

V=LWH

The operation of multiplication is used in the formula

so

The inverse operation of division should be used to isolate the variable H

so

Divide both sides by LW

\frac{V}{LW}=\frac{LWH}{LW}

simplify

H=\frac{V}{LW}

6 0
3 years ago
The lower supports are and the area of the two supports is square meters. The upper arch can be decomposed as one semicircle wit
Galina-37 [17]

Answer:

 The lower supports are <u>Congruent Rectangles</u> and the area of the two supports is<u> 24 square meters.</u>

The upper arch can be decomposed as one semicircle with radius<u> 6 </u>meters minus a semicircle with radius 3 meters.

The area of the archway is <u>(13.5 π</u> + 24) square meters.

Step-by-step explanation:

See attachment for the firgure,

In order to determine the area of archway = The area of upper support + area of lower support.

As given, the lower support are two congruent rectangles consists of dimension 3 m × 4 m

Therefore, the area of lower support can be written as,

The area of lower support = 3 × 4 + 3 × 4 = 12 + 12 = 24 square m.

Now, the upper support arch can be decomposed as the two concentric semi circles having radius 3 m and 6 m,

Hence, the area of the upper support = Area of semi circle having radius i.e 6 m - Area of semi circle having radius i.e 3 m

=> π6²/2 - π3²/2= 27π/2= 13.5π square m

Therefore, the area of the archway =  (13.5 π + 24) square meters

4 0
3 years ago
PLASE HELP ME ASAP
CaHeK987 [17]

Answer:

D

Step-by-step explanation:

I answered it right

6 0
3 years ago
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