Answer:
Rectangle
Step-by-step explanation:
Kite is a quadrilateral in which exactly two pair of adjacent sides are equal.
Rectangle is a quadrilateral in which opposite sides are equal.
Square and rhombus are a quadrilaterals in which all sides are equal.
Given points: 
We need to find whether these points represent coordinates of kite , rectangle , rhombus or square .
Let the points be 
We know that distance between points
is given by 

Here, AB = CD and AD = BC, so the given points are coordinates of the rectangle .