The given quadrilateral ABCD is a parallelogram since the opposite sides are of same length AB and DC is 4 and AD and BC is 2.
<u>Step-by-step explanation</u>:
ABCD is a quadrilateral with their opposite sides are congruent (equal).
The both pairs of opposite sides are given as AB = 3 + x
, DC = 4x
, AD = y + 1
, BC = 2y.
- AB and DC are opposite sides and have same measure of length.
- AD and BC are opposite sides and have same measure of length.
<u>To find the length of AB and DC :</u>
AB = DC
3 + x = 4x
Keep x terms on one side and constant on other side.
3 = 4x - x
3 = 3x
x = 1
Substiute x=1 in AB and DC,
AB = 3+1 = 4
DC = 4(1) = 4
<u>To find the length of AD and BC :</u>
AD = BC
y + 1 = 2y
Keep y terms on one side and constant on other side.
2y-y = 1
y = 1
Substiute y=1 in AD and BC,
AD = 1+1 = 2
BC = 2(1) = 2
Therefore, the opposite sides are of same length AB and DC is 4 and AD and BC is 2. The given quadrilateral ABCD is a parallelogram.
2√2
= 2√2
B)
√3(√2+380√2-80)
= -80√3+381√6
I hope that's help and sorry for the late answer !
Answer:
the first one
Step-by-step explanation:
because the slope for the second one has no follow of origin
I would draw the triangle then it would be easier to answer. It is not an equilateral because it is not equal on all sides. Perhaps scalene because all the sides are not the same.
Answer:
y=1/4x+3
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(6-2)/(12-(-4))=4/(12+4)=4/16=1/4
y-y1=m(x-x1)
y-2=1/4(x-(-4))
y-2=1/4(x+4)
y=1/4x+4/4+2
y=1/4x+1+2
y=1/4x+3
