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3 years ago

A "thrift" is another name for a commercial bank. True or False

1 answer:

4 0

A thrift is a kind of bank that arranges mortgages (mostly for home ownership) and sets up accounts to receive deposits.

The statement is actually false. The difference is in who they can borrow from and whether or not they are set up for profit. Thrifts are usually non profit.

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Simplify square root 3y diviede by square root of y

Nataly [62]

Answer:

Step-by-step explanation:

√3y/√y

= √(3y/y)

= √3

5 0

3 years ago

A rectangle has a length of 9 inches and a width of 12 inches. This rectangle is dilated by a scale factor of 3.5 to create a ne

Nat2105 [25]

Divide both length and width by the dialtion factor and that will be the dimensions of the new rectangle. 2.5714in by 3.4286in. Round as needed

8 0

3 years ago

Read 2 more answers

What is the total price of a $60 restaurant tab if you leave a 15% tip?

7nadin3 [17]

Answer:

$69 is the total cost of the bill

Step-by-step explanation:

60(1.15)

60 is the cost of the bill, and the 1.15 is the added tax plus the previous $60.

Put 60(1.15) into a calculator and

$69

8 0

3 years ago

What is the midpoint of equation if N(10, −14) and P(−16, −4)?

meriva

Answer:

The answer is

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

$M = ( \frac{x_1 + x_2}{2} , \: \frac{y_1 + y_2}{2} ) \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question

N(10, −14) and P(−16, −4)

The midpoint is

$M = ( \frac{10 - 16}{2} \: , \: \frac{ - 14 - 4}{2} ) \\ = ( - \frac{6}{2} \: , \: - \frac{18}{2} )$

We have the final answer as

Hope this helps you

6 0

3 years ago

Identify the number of solutions of the system of linear equations. 5x+y−z=6 x+y+z=2 12x+4y=10

asambeis [7]

Answer:

x = $\frac{19}{12}$ y = $(-\frac{9}{4} )$ z = $\frac{8}{3}$ One solution for each variable.

Step-by-step explanation:

5x + y − z = 6

x + y + z = 2

12x + 4y = 10

The first thing we need to do is solve for x in the 3rd equation because it inly have 2 variables, x and y.

12x + 4y = 10 Subtract 4y from each side

12x + 4y - 4y = 10 - 4y

12x = 10 - 4y Pull 2 out on the right side

12x = 2(5 - 2y) Divide each side by 12

12x/12 = 2(5 - 2y)/12

x = 2(5 - 2y)/12

x = (5 - 2y)/6

Now we plug in our x value into the 2nd equation and solve for z

x + y + z = 2

$\frac{5-2y}{6}$ + y + z = 2 Multiply each side by 6

6( $\frac{5-2y}{6}$ + y + z) = 2 * 6

6( $\frac{5-2y}{6}$ + y + z) = 12

5 - 2y + 6y + 6z = 12 Combine like terms

5 + 4y + 6z = 12 Subtract 5 from each side

5 - 5 + 4y + 6z = 12 - 5

4y + 6z = 7 Subtract 4y from each side

4y - 4y + 6z = 7 - 4y

6z = 7 - 4y Divide each side by 6

6z/6 = (7 - 4y)/6

z = (7 - 4y)/6

Now we solved for z and x, so in the 1st equation we plug in x and z.

5x + y − z = 6

5( $\frac{5-2y}{6}$ ) + y - $\frac{7-4y}{6}$ = 6 Multiply each side by 6

6*(5( $\frac{5-2y}{6}$ ) ) + 6y - 6( $\frac{7-4y}{6}$ ) = 6*6

6*(5( $\frac{5-2y}{6}$ ) ) + 6y - 6( $\frac{7-4y}{6}$ ) = 36

5(5 - 2y) + 6y - 7 - 4y = 36

25 - 10y + 6y - 7 - 4y = 36 Rearrange to make it easier to combine terms.

25 - 7 - 10y + 6y - 4y = 36

18 - 8y = 36 Subtract 18 from each side.

18 - 18 - 8y = 36 - 18

- 8y = 36 - 18

- 8y = 18 Divide each side by -8

- 8y/-8 = 18/- 8

y = 18/- 8

y = - 9/4

Now we plug our answer for y back into the 3rd equation and solve for the value of x.

12x + 4y = 10

12x + 4 $(-\frac{9}{4} )$ = 10

12x - 9 = 10 Add 9 to each side

12x - 9 + 9 = 10 + 9

12x = 10 + 9

12x = 19 Divide each side by 12

12x/12 = 19/12

x = 19/12

Now we have a value for x and y so plug these into the 2nd equation to sovle for z.

x + y + z = 2

$\frac{19}{12}$ + $(-\frac{9}{4} )$ + z = 2 We need to find the common denominator in order to add.

$(-\frac{9}{4} )$ * $\frac{3}{3}$ = $-\frac{27}{12}$

$\frac{19}{12}$ $-\frac{27}{12}$ + z = 2

$-\frac{8}{12}$ + z = 2 Add $-\frac{8}{12}$ to each side

$-\frac{8}{12}$ $+ \frac{8}{12}$ + z = 2 $+ \frac{8}{12}$

z = 2 $+ \frac{8}{12}$ Reduce $+ \frac{8}{12}$ to $\frac{2}{3}$

z = 2 + $\frac{2}{3}$ To add find a common denominator.

$2 * \frac{3}{3} = \frac{6}{3}$

z = $\frac{6}{3}$ + $\frac{2}{3}$

z = $\frac{8}{3}$

So there is 1 solution for each variable.

8 0

3 years ago