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3 years ago

What is the sum of an infinite geometric series if the first term is 81 and the common ratio is 2⁄3?

Mathematics

1 answer:

Marrrta [24]3 years ago

4 0

the sum to infinity of a geometric series = $\frac{a}{1-r}$

where a is the first term and r the common ratio

= $\frac{81}{\frac{1}{3} }$ = 81 × 3 = 243

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How do I find out how to work out , y=mx+c ???

hjlf

Y=mx+c isn't an equation to solve. It's the slope-intercept formula for graphing lines.
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3 years ago

Read 2 more answers

Theresa is 14 years younger than her brother Jonathan. Together, their total age in years is 35. A) How many years old is Theres

ikadub [295]

A) The age of Theresa is 10 years 6 months old

B) Jonathan age is 24 years and 6 months old

Solution:

Given, Theresa is 14 years younger than her brother Jonathan.

Let the age of Theresa be "n" years

Then the age of Jonathan will be "n + 14" years

Together, their total age in years is 35

A) Finding age of Theresa:

Jonathan age + Theresa age = 35

n + 14 + n = 35

2n + 14 = 35

2n = 35 - 14

2n = 21

n = 10.5

So, age of Theresa is 10 years 6 months

B) Finding age of Jonathan

Now, we know that n = 10.5

Then Jonathan age = n + 14 = 10.5 + 14 = 24.5 years

So, Jonathan is 24 years and 6 months old

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3 years ago

The force of gravity on Mars is different than on Earth. The function of the same situation on Mars would be represented by the

sweet-ann [11.9K]

Answer:

If thrown up with the same speed, the ball will go highest in Mars, and also it would take the ball longest to reach the maximum and as well to return to the ground.

Step-by-step explanation:

Keep in mind that the gravity on Mars; surface is less (about just 38%) of the acceleration of gravity on Earth's surface. Then when we use the kinematic formulas:

$v=v_0+a\,*\,t\\y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2$

the acceleration (which by the way is a negative number since acts opposite the initial velocity and displacement when we throw an object up on either planet.

Therefore, throwing the ball straight up makes the time for when the object stops going up and starts coming down (at the maximum height the object gets) the following:

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When we use this to replace the 't" in the displacement formula, we et:

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This tells us that the smaller the value of "g", the highest the ball will go (g is in the denominator so a small value makes the quotient larger)

And we can also answer the question about time, since given the same initial velocity $v_0$ , the smaller the value of "g", the larger the value for the time to reach the maximum, and similarly to reach the ground when coming back down, since the acceleration is smaller (will take longer in Mars to cover the same distance)

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3 years ago

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Answer:

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3 years ago

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3 years ago