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3 years ago

Write using exponent (-2) (-2) (-2) (-2)

Mathematics

2 answers:

Sergio [31]3 years ago

7 0

Your answer is to be 16

poizon [28]3 years ago

3 0

It would be
$( - 2) {}^{4}$

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A garage floor measures 150 feet by 120 feet. A scale drawing of the floor on grid paper uses a scale of 1 unit and 15 feet.What

vova2212 [387]

Answer:

The dimensions of the drawing are 10 units by 8 units

Step-by-step explanation:

we know that

The scale drawing is $\frac{1}{15}\ \frac{unit}{feet}$

That means ---> 1 unit in the drawing represent 15 feet in the actual

To find out the dimensions of the drawing, multiply the actual dimensions by the scale drawing

$150\ ft=150(\frac{1}{15})=10\ units$

$120\ ft=120(\frac{1}{15})=8\ units$

therefore

The dimensions of the drawing are 10 units by 8 units

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3 years ago

Solve for b.<br><br> -3b = 9 - 4b<br><br> B=

BlackZzzverrR [31]

Answer:

b=9

Step-by-step explanation:

move the 4b over to the other side by adding it to both sides

$-3b(+4b)=9-4b(+4b)$

$1b=9$

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3 years ago

Which two triangles are congruent? Complete the congruence statement.

shtirl [24]

Answer:

tsu and hgi

Step-by-step explanation:

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3 years ago

How to find matrics M

makkiz [27]

$\left[\begin{array}{ccc}9&7\\-4&2\end{array}\right] -4M=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\qquad(*) \\\\M=\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]\to4M=\left[\begin{array}{ccc}4a&4b\\4c&4d\end{array}\right]$

$(*)\qquad\left[\begin{array}{ccc}9&7\\-4&2\end{array}\right] -\left[\begin{array}{ccc}4a&4b\\4c&4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\\\\left[\begin{array}{ccc}9-4a&7-4b\\-4-4c&2-4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\.\qquad\qquad\qquad\qquad\ \ \ \Downarrow\\(_{11})\qquad9-4a=-3\ \ \ |-9\\-4a=-12\ \ \ \ |:(-4)\\a=3\\\\(_{12})\qquad7-4b=3\ \ \ \ |-7\\-4b=-4\ \ \ \ |:(-4)\\b=1$

$(_{21})\qquad-4-4c=4\ \ \ \ |+4\\-4c=8\ \ \ \ |:(-4)\\c=-2\\\\(_{22})\qquad2-4d=-18\ \ \ \ |-2\\-4d=-20\ \ \ \ \ |:(-4)\\d=5\\\\Answer:\ A.\ M=\left[\begin{array}{ccc}3&1\\-2&5\end{array}\right]$

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3 years ago

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nignag [31]

Answer:

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Step-by-step explanation:

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3 years ago

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